Question
Solve for
and
simultaneously:
1.3 * Show that
is even for all positive integer values of
1.3 * Show that
Ask by Cervantes Morrison. in South Africa
Mar 22,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The solutions are
and
. Additionally, the expression
is even for all positive integers
.
Solution
Step 1. Solve the system of equations
We are given:
-
Solve the first equation for
: -
Substitute
into the second equation: -
Expand and simplify:
-
Divide the entire equation by
: -
Factor the quadratic:
-
Solve for
: - If
, then . - If
, then .
- If
-
Find the corresponding
-values using : - For
: - For
:
- For
Thus, the solutions are:
Step 2. Show that
is even for all positive integers
Given the expression:
follow these steps:
-
Factor out the common factor
: -
Simplify the expression inside the parentheses:
-
Hence, the expression becomes:
-
Since
is even, the product is even for any integer .
Thus,
is even for all positive integers
.
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Extra Insights
To solve for
and
from the equations
and
, we can start by rearranging the first equation to express
:
Next, we can substitute this expression for
into the second equation:
This simplifies to:
Dividing the entire equation by 2 gives:
Factoring the quadratic yields:
Thus,
or
. Since we’re looking for positive integer values, we take
. Substituting
back into our equation for
:
So, we find that one solution is
.
Now, addressing the second part: to show that
is even for all positive integers
, we rewrite it as:
The term
is clearly even since it’s multiplied by 4. The crucial factor is
. Noticing that if
,
is always an even number since it combines a fraction (the 2) with a base of 5 (an odd number) raised to a positive integer power. Hence, the whole expression results in an even number for all positive integers
.