Question
The dollar value \( v(t) \) of a certain car model that is \( t \) years old is given by the following exponential function. \[ v(t)=24,500(0.84)^{t} \] Find the value of the car after 4 years and after 10 years. Round your answers to the nearest dollar as necessary. value after 4 years: value after 10 years:
Ask by Gonzalez Alexander. in the United States
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
After 4 years, the car is worth \$12,298. After 10 years, it is worth \$4,291.
Solution
To determine the value of the car after 4 years and after 10 years using the exponential depreciation function:
\[
v(t) = 24,500 \times (0.84)^t
\]
### **1. Value After 4 Years (\( t = 4 \))**
\[
v(4) = 24,500 \times (0.84)^4
\]
First, calculate \( (0.84)^4 \):
\[
(0.84)^4 \approx 0.4979
\]
Then, multiply by the initial value:
\[
v(4) = 24,500 \times 0.4979 \approx 12,298 \text{ dollars}
\]
### **2. Value After 10 Years (\( t = 10 \))**
\[
v(10) = 24,500 \times (0.84)^{10}
\]
First, calculate \( (0.84)^{10} \):
\[
(0.84)^{10} \approx 0.1751
\]
Then, multiply by the initial value:
\[
v(10) = 24,500 \times 0.1751 \approx 4,291 \text{ dollars}
\]
### **Final Answers**
- **Value after 4 years:** \$12,298
- **Value after 10 years:** \$4,291
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Extra Insights
To find the value of the car after 4 years, we substitute \( t = 4 \) into the equation: \[ v(4) = 24,500(0.84)^{4} \approx 24,500 \times 0.497871 = 12,195.88 \] Rounding to the nearest dollar, the value after 4 years is approximately **$12,196**. Next, for the value after 10 years, we substitute \( t = 10 \): \[ v(10) = 24,500(0.84)^{10} \approx 24,500 \times 0.253552537 = 6,215.01 \] Rounding to the nearest dollar, the value after 10 years is approximately **$6,215**.