Smplify $$ \frac{\sqrt{4^{2 n-4}} \cdot 8^{5-2 n}}{\sqrt{16-2 n}} $$

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Calculate or simplify the expression $$ \frac{\sqrt{4^{2n-4}} \cdot 8^{5-2n}}{\sqrt{16-2n}} $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{\sqrt{4^{2n-4}}	imes 8^{5-2n}}{\sqrt{16-2n}}$$
- step1: Simplify the root:
  $$\frac{4^{n-2}	imes 8^{5-2n}}{\sqrt{16-2n}}$$
- step2: Multiply:
  $$\frac{2^{-4n+11}}{\sqrt{16-2n}}$$
- step3: Factor the expression:
  $$\frac{\sqrt{2}	imes 2^{-4n+\frac{21}{2}}}{\sqrt{2}	imes \sqrt{8-n}}$$
- step4: Reduce the fraction:
  $$\frac{2^{-4n+\frac{21}{2}}}{\sqrt{8-n}}$$
- step5: Simplify:
  $$\frac{2^{-4n+\frac{21}{2}}\sqrt{8-n}}{8-n}$$
The simplified form of the expression $$ \frac{\sqrt{4^{2n-4}} \cdot 8^{5-2n}}{\sqrt{16-2n}} $$ is $$ \frac{2^{-4n+\frac{21}{2}}\sqrt{8-n}}{8-n} $$.
The simplified form of the expression is $$ \frac{2^{-4n+\frac{21}{2}}\sqrt{8-n}}{8-n} $$.

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