\( \$ 200 \) are deposited in an account with \( 6 \% \) interest rate, compounded continuously. What is the balance after 5 years? \[ F=\$[?] \] Round to the nearest cent.
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To calculate the future balance for an investment compounded continuously, you can use the formula: \[ F = P e^{rt} \] where: - \( P \) is the principal amount (\$200) - \( r \) is the interest rate (0.06) - \( t \) is the time in years (5) - \( e \) is the base of the natural logarithm, approximately equal to 2.71828. Plugging in the values: \[ F = 200 \times e^{0.06 \times 5} \] Calculating the exponent: \[ 0.06 \times 5 = 0.3 \] Now, calculating \( e^{0.3} \): \[ e^{0.3} \approx 1.34986 \] Now plug this back into the formula: \[ F \approx 200 \times 1.34986 \approx 269.972 \] Rounding to the nearest cent, the balance after 5 years is: \[ F \approx \$269.97 \]