Question
a) \( 8 y-16 y^{2} \) \( 4 y^{2} \) b) \( 9-4 a^{2} \) \( 4 a^{2}-16 a+15 \) c) \( 6 x^{2}+x y-15 y^{2} \) \( 6 x^{2}+10 x y \) d) \( x^{2}+2 x^{2}-4 x-8 \) \( 6 x^{2}-5 x-14 \)
Ask by Pierce Park. in South Africa
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
- **Part a:** \( 8y - 20y^2 \)
- **Part b:** \( 16a - 8a^2 - 6 \)
- **Part c:** \( 12x^2 + 11xy - 15y^2 \)
- **Part d:** \( 9x^2 - 9x - 22 \)
Solution
Let's solve each part step by step, simplifying the expressions provided.
### Part a
We have the expressions:
1. \( 8y - 16y^2 \)
2. \( 4y^2 \)
**Step 1: Combine the expressions.**
To combine these, we can rewrite the first expression:
\[
8y - 16y^2 = 8y - 4y^2 \cdot 4
\]
Now, we can combine them:
\[
8y - 16y^2 - 4y^2 = 8y - 20y^2
\]
### Part b
We have the expressions:
1. \( 9 - 4a^2 \)
2. \( 4a^2 - 16a + 15 \)
**Step 1: Combine the expressions.**
To combine these, we can rewrite the first expression:
\[
9 - 4a^2 - (4a^2 - 16a + 15) = 9 - 4a^2 - 4a^2 + 16a - 15
\]
Now, simplify:
\[
= 16a - 8a^2 - 6
\]
### Part c
We have the expressions:
1. \( 6x^2 + xy - 15y^2 \)
2. \( 6x^2 + 10xy \)
**Step 1: Combine the expressions.**
To combine these, we can rewrite the first expression:
\[
6x^2 + xy - 15y^2 + 6x^2 + 10xy = 12x^2 + 11xy - 15y^2
\]
### Part d
We have the expressions:
1. \( x^2 + 2x^2 - 4x - 8 \)
2. \( 6x^2 - 5x - 14 \)
**Step 1: Combine the expressions.**
To combine these, we can rewrite the first expression:
\[
x^2 + 2x^2 - 4x - 8 = 3x^2 - 4x - 8
\]
Now, combine with the second expression:
\[
3x^2 - 4x - 8 + 6x^2 - 5x - 14 = 9x^2 - 9x - 22
\]
### Summary of Results
- **Part a:** \( 8y - 20y^2 \)
- **Part b:** \( 16a - 8a^2 - 6 \)
- **Part c:** \( 12x^2 + 11xy - 15y^2 \)
- **Part d:** \( 9x^2 - 9x - 22 \)
Reviewed and approved by the UpStudy tutoring team
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Bonus Knowledge
For part (a), you can factor out the common term in \( 8y - 16y^{2} \) and \( 4y^{2} \), which leads to \( 8y(1 - 2y) \) and \( 4y^{2} \) ultimately showing how common factors simplify expressions. In part (b), factoring \( 9 - 4a^{2} \) generates a difference of squares, giving \( (3 - 2a)(3 + 2a) \), while the quadratic expression \( 4a^{2} - 16a + 15 \) could be approached with the quadratic formula or grouping. This exercise illustrates how different strategies can lead to a clearer understanding of polynomial identities!