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Simplify. \( \frac{6}{x-2}-\frac{x+7}{x+2} \)

Ask by Malone Pierce. in the United States
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ \frac{-x^2 + x + 26}{x^2 - 4} \]

Solution

To simplify the expression: \[ \frac{6}{x-2} - \frac{x+7}{x+2} \] **Step 1: Find a Common Denominator** The common denominator for the two fractions is \((x - 2)(x + 2)\). **Step 2: Rewrite Each Fraction with the Common Denominator** \[ \frac{6}{x-2} = \frac{6(x + 2)}{(x - 2)(x + 2)} \] \[ \frac{x+7}{x+2} = \frac{(x + 7)(x - 2)}{(x - 2)(x + 2)} \] **Step 3: Combine the Fractions** \[ \frac{6(x + 2) - (x + 7)(x - 2)}{(x - 2)(x + 2)} \] **Step 4: Expand and Simplify the Numerator** First, expand both terms in the numerator: \[ 6(x + 2) = 6x + 12 \] \[ (x + 7)(x - 2) = x^2 + 7x - 2x - 14 = x^2 + 5x - 14 \] Now, subtract the second expanded term from the first: \[ 6x + 12 - (x^2 + 5x - 14) = 6x + 12 - x^2 - 5x + 14 = -x^2 + x + 26 \] **Step 5: Write the Final Simplified Expression** \[ \frac{-x^2 + x + 26}{(x - 2)(x + 2)} \] This can also be written as: \[ \frac{-x^2 + x + 26}{x^2 - 4} \] **Final Answer:** \[ \boxed{\dfrac{-\,x^{2} + x + 26}{\,x^{2} - 4\,}} \]

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Mind Expander

To simplify \( \frac{6}{x-2}-\frac{x+7}{x+2} \), we first find a common denominator, which is \( (x-2)(x+2) \). Rewriting each fraction with the common denominator, we have: \[ \frac{6(x+2)}{(x-2)(x+2)} - \frac{(x+7)(x-2)}{(x-2)(x+2)} \] Now, we can combine the fractions: \[ \frac{6(x+2) - (x+7)(x-2)}{(x-2)(x+2)} \] Next, we expand both numerators: 1. For the first term: \( 6(x+2) = 6x + 12 \) 2. For the second term: \( (x+7)(x-2) = x^2 - 2x + 7x - 14 = x^2 + 5x - 14 \) Combining these gives us: \[ 6x + 12 - (x^2 + 5x - 14) = 6x + 12 - x^2 - 5x + 14 = -x^2 + x + 26 \] Thus, we have: \[ \frac{-x^2 + x + 26}{(x-2)(x+2)} \] This is our simplified result.

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