Find the slope and the $$ y $$-intercept of the graph of the equation. $$ 8 x+9 y=36 $$ slope $$ y $$-intercept $$ \quad(x, y)=(\square) $$

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To find the slope and the $$ y $$-intercept of the equation $$ 8x + 9y = 36 $$, we can rewrite the equation in slope-intercept form, which is $$ y = mx + b $$, where $$ m $$ is the slope and $$ b $$ is the $$ y $$-intercept.

Starting with the original equation:

$$
8x + 9y = 36
$$

We can isolate $$ y $$ by following these steps:

1. Subtract $$ 8x $$ from both sides:

$$
9y = -8x + 36
$$

2. Divide every term by $$ 9 $$:

$$
y = -\frac{8}{9}x + 4
$$

Now, we can identify the slope and the $$ y $$-intercept from the equation $$ y = -\frac{8}{9}x + 4 $$:

- The slope $$ m $$ is $$ -\frac{8}{9} $$.
- The $$ y $$-intercept $$ b $$ is $$ 4 $$, which corresponds to the point $$ (0, 4) $$.

Thus, the slope and $$ y $$-intercept are:

- Slope: $$ -\frac{8}{9} $$
- $$ y $$-intercept: $$ (x, y) = (0, 4) $$

So, the final answers are:

**Slope:** $$ -\frac{8}{9} $$

**$$ y $$-intercept:** $$ (0, 4) $$
Slope: $$ -\frac{8}{9} $$, $$ y $$-intercept: $$ (0, 4) $$

Find the slope and the \( y \)-intercept of the graph of the equation. \[ 8 x+9 y=36 \] slope \( y \)-intercept \( \quad(x, y)=(\square) \)

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