Brody and his children went into a movie theater and he bought $$ \$ 44.50 $$ worth of drinks and pretzels. Each drink costs $$ \$ 6 $$ and each pretzel costs $$ \$ 3.25 $$. He bought a total of 12 drinks and pretzels altogether. Determine the number of drinks and the number of pretzels that Brody bought. Answer Attempt 1 out of to Brody bought $$ \square $$ drinks and $$ \square $$ pretzels.

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Let's determine the number of drinks and pretzels Brody bought using a system of equations.

**Let:**
- $$ d $$ = number of drinks
- $$ p $$ = number of pretzels

**Given:**
1. The total number of items (drinks and pretzels) is 12:
   $$
   d + p = 12
   $$
2. The total cost is \$44.50, with each drink costing \$6 and each pretzel costing \$3.25:
   $$
   6d + 3.25p = 44.50
   $$

**Step 1: Solve the first equation for one variable**
$$
d = 12 - p
$$

**Step 2: Substitute $$ d $$ in the second equation**
$$
6(12 - p) + 3.25p = 44.50
$$

**Step 3: Distribute and combine like terms**
$$
72 - 6p + 3.25p = 44.50
$$
$$
72 - 2.75p = 44.50
$$

**Step 4: Isolate $$ p $$**
$$
-2.75p = 44.50 - 72
$$
$$
-2.75p = -27.50
$$
$$
p = \frac{-27.50}{-2.75}
$$
$$
p = 10
$$

**Step 5: Find $$ d $$ using the value of $$ p $$**
$$
d = 12 - p = 12 - 10 = 2
$$

**Conclusion:**
Brody bought **2 drinks** and **10 pretzels**.

**Answer Attempt 1 out of to**
Brody bought $$ \boxed{2} $$ drinks and $$ \boxed{10} $$ pretzels.
Brody bought 2 drinks and 10 pretzels.

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