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Add \& Subtract In Fraction Word Problems Katle popped \( \frac{3}{6} \) of the balloons. Jamll popped \( \frac{2}{6} \) of the balloons. What fractlon of the balloons dld they pop altogether? Which equation models thls problem? \[ \frac{2}{6}-\frac{3}{6}=\frac{4}{6} \] \( \frac{3}{6}-\frac{2}{6}=\frac{1}{6} \) \( \frac{3}{6}+\frac{2}{6}=\frac{5}{6} \) \( \frac{3}{6}+\frac{3}{6}=\frac{6}{6} \)

Ask by Boone Hodges. in Saudi Arabia
Feb 03,2025

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Answer

The correct equation is \( \frac{3}{6} + \frac{2}{6} = \frac{5}{6} \).

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Extra Insights

When solving fraction word problems like this, it’s essential to remember that you want to combine the parts to find the whole. In this case, Katle and Jamll have popped \( \frac{3}{6} \) and \( \frac{2}{6} \) of the balloons, respectively. When you add those fractions together, you end up with \( \frac{5}{6} \) of the balloons popped, making it clear that they're just a whisker away from completely deflating the party! Now, regarding the equations provided, the correct one represents the sum of the fractions popped by each: \( \frac{3}{6} + \frac{2}{6} = \frac{5}{6} \). Remember, when adding fractions with the same denominator, simply add the numerators while keeping the denominator intact. So, essentially, Katle and Jamll turned the balloon bash into a nearly balloon-free zone!

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