Question
upstudy study bank question image url

19.2 The following sequence has the property that the sequence of numerators is arithmetic and the sequence of denominators is geometric: \( \begin{array}{lll}\text { 19.2.1 } & \text { Write down the FOURTH term of the sequence. } & \text { (1) } \\ 19.2 .2 & \text { Determine a formula for the } n^{\text {th }} \text { term. } \\ 19.2 .3 & \text { Determine the } 500^{\text {th }} \text { term of the sequence. } & \text { (3) } \\ 19.2 .4 & \text { Which will be the first term of the sequence to have a } & \text { (2) } \\ \text { NUMERATOR which is less than }-59 \text { ? } & \text { (3) }\end{array} \)

Ask by Mckenzie May. in South Africa
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

To solve the sequence problem, you need to provide the first two terms of the sequence. Once I have the initial fraction and the second term, I can determine the common difference for the numerators and the common ratio for the denominators. This information will allow me to find the fourth term, the general formula for the nth term, the 500th term, and identify the first term with a numerator less than -59.

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Reviewed and approved by the UpStudy tutoring team

Mind Expander

To explore the sequence where the numerators form an arithmetic sequence and the denominators form a geometric sequence, let’s assume the numerators are of the form \( a + (n-1)d \) and the denominators as \( b \cdot r^{n-1} \) where \( a \), \( d \), \( b \), and \( r \) are constants. For the fourth term of the sequence, you simply plug in \( n = 4 \) into both formulas to get: \[ \text{Fourth term} = \frac{a + 3d}{b \cdot r^3} \] To find the nth term, the formula can be compactly expressed as: \[ \text{nth term} = \frac{a + (n-1)d}{b \cdot r^{n-1}} \] Now, to find the 500th term, substitute \( n = 500 \): \[ \text{500th term} = \frac{a + 499d}{b \cdot r^{499}} \] Lastly, to determine when the numerator goes below -59: \[ a + (n-1)d < -59 \] You can solve for \( n \) to find the minimum term where this holds true. Now, let's add some spice with extra fun facts! Imagine if this sequence represented a magical journey where each term leads you further away from a treasure guarded by complicated fractions! The arithmetic numerators march forward like brave knights, while the geometric denominators stack up the fortifications, making the adventure both steady and daring at once. Also, for those stat lovers, did you know that sequences like this pop up in real-world scenarios too? For example, in finance, when dealing with annuities (a sequence of cash flows) where payment amounts increase linearly (arithmetic) while the time intervals between payments grow exponentially (geometric). So whether seeking treasure or balancing budgets, these sequences are everywhere!

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy