Use synthetic division to find the result when \( 4 x^{4}+25 x^{3}+2 x^{2}-25 x-8 \) is divided by \( x+6 \). If there is a remainder, express the result in the form \( q(x)+\frac{r(x)}{b(x)} \)
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To perform synthetic division of the polynomial \( 4x^4 + 25x^3 + 2x^2 - 25x - 8 \) by \( x + 6 \), we first rewrite \( x + 6 \) as \( x - (-6) \). Now, we use -6 in our synthetic division process: 1. Write down the coefficients of the polynomial: \( 4, 25, 2, -25, -8 \). 2. Set up the synthetic division: \[ \begin{array}{r|rrrrr} -6 & 4 & 25 & 2 & -25 & -8 \\ & & -24 & -6 & 24 & 6 \\ \hline & 4 & 1 & -4 & -1 & -2 \\ \end{array} \] 3. Add each column: - First column: \( 4 \) - Second column: \( 25 - 24 = 1 \) - Third column: \( 2 - 6 = -4 \) - Fourth column: \( -25 + 24 = -1 \) - Fifth column: \( -8 + 6 = -2 \) The final row \( 4, 1, -4, -1 \) represents the coefficients of the quotient, and the last number, -2, is the remainder. So, we can write the result of the division as: \[ q(x) = 4x^3 + 1x^2 - 4x - 1 \quad \text{and} \quad r(x) = -2 \] Thus, the result when \( 4x^4 + 25x^3 + 2x^2 - 25x - 8 \) is divided by \( x + 6 \) is: \[ 4x^3 + x^2 - 4x - 1 - \frac{2}{x + 6} \] or in the desired form: \[ 4x^3 + x^2 - 4x - 1 + \frac{-2}{x + 6} \] So, finally: \[ q(x) + \frac{r(x)}{b(x)} = 4x^3 + x^2 - 4x - 1 + \frac{-2}{x + 6} \]