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Solve \( \log _{5}(5 x+2)=1 \)

Ask by Higgins Griffin. in Canada
Jan 24,2025

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Answer

\( x = \frac{3}{5} \)

Solution

To solve the equation \( \log _{5}(5x + 2) = 1 \), follow these steps: 1. **Understand the logarithmic equation**: The equation \( \log_b(a) = c \) can be rewritten in its exponential form as \( b^c = a \). 2. **Apply the exponential form**: \[ \log _{5}(5x + 2) = 1 \quad \Rightarrow \quad 5^1 = 5x + 2 \] Simplifying the left side: \[ 5 = 5x + 2 \] 3. **Solve for \( x \)**: \[ 5x + 2 = 5 \] Subtract 2 from both sides: \[ 5x = 3 \] Divide both sides by 5: \[ x = \frac{3}{5} \] **Final Answer:** \( x = \dfrac{3}{5} \)

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Bonus Knowledge

To solve the equation \( \log_{5}(5x + 2) = 1 \), we start by using the definition of logarithms. The equation states that \( 5^{1} = 5x + 2 \). This simplifies to: \[ 5 = 5x + 2 \] Next, we subtract 2 from both sides: \[ 5 - 2 = 5x \] This gives us: \[ 3 = 5x \] Now, we divide both sides by 5: \[ x = \frac{3}{5} \] Therefore, the solution to the equation \( \log_{5}(5x + 2) = 1 \) is \( x = \frac{3}{5} \).

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