What are the zeros of the equation $$ y+9 x=x^{3} $$ ? $$ (3,0) $$ $$ (0,-3) $$ $$ (0,0),(3,0) $$ and $$ (-3,0) $$ $$ (0,3),(-3,0) $$ and $$ (9,0) $$ $$ (0,0),(0,9) $$ and $$ (0,-9) $$

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To find the zeros of the equation $$ y + 9x = x^{3} $$, we look for the points where $$ y = 0 $$ (i.e., the x-intercepts).

1. **Set $$ y = 0 $$:**
   $$
   0 + 9x = x^{3}
   $$
   $$
   x^{3} - 9x = 0
   $$
   
2. **Factor the equation:**
   $$
   x(x^{2} - 9) = 0
   $$
   $$
   x(x - 3)(x + 3) = 0
   $$
   
3. **Solve for $$ x $$:**
   $$
   x = 0, \quad x = 3, \quad x = -3
   $$
   
4. **Identify the corresponding points:**
   $$
   (0, 0), \quad (3, 0), \quad (-3, 0)
   $$

**Therefore, the zeros of the equation are** $$ (0,0), (3,0) $$ **and** $$ (-3,0) $$.

**Answer:** $$ (0,0),(3,0) $$ and $$ (-3,0) $$
The zeros of the equation $$ y + 9x = x^{3} $$ are $$ (0,0) $$, $$ (3,0) $$, and $$ (-3,0) $$.

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