Find the roots of the factored polynomial. \[ \begin{array}{l}x^{2}(x-1) \\ \text { Write your answer as a list of values separated by commas. } \\ x= \\ \text { Submit }\end{array} \]

To find the roots of the factored polynomial \( x^{2}(x-1) \), we can set the equation equal to zero: \[ x^{2}(x-1) = 0. \] This gives us two factors to consider: 1. \( x^{2} = 0 \) 2. \( x - 1 = 0 \) For the first factor \( x^{2} = 0 \), the root is: \[ x = 0. \] For the second factor \( x - 1 = 0 \), the root is: \[ x = 1. \] However, since \( x^{2} \) contributes a double root at \( x = 0 \), we can list the roots as: \[ x = 0, 0, 1. \] You can write the distinct roots as \( 0, 1 \) or include their multiplicities as \( 0, 0, 1 \). For the sake of simplicity, the final answer as a list of distinct values is: \[ x = 0, 1. \]