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20 Draw a spinner for which \( \operatorname{Pr}( \) green \( )=2 \operatorname{Pr}( \) blue \( ) \) \( \operatorname{Pr}( \) blue \( )=2 \operatorname{Pr}( \) brown \( ) \) \( \operatorname{Pr}( \) brown \( )=2 \operatorname{Pr}( \) pink \( ) \) and \( \operatorname{Pr}( \) pink \( )=2 \operatorname{Pr}( \) red \( ) \)

Ask by Wells Cruz. in Hong Kong
Jan 06,2025

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To create the spinner, divide the circle into five sectors with the following angles: - **Green:** 185.8° - **Blue:** 92.9° - **Brown:** 46.5° - **Pink:** 23.2° - **Red:** 11.6°

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Bonus Knowledge

Let's denote the probability of red as \( r \). According to the relationships given, we can express the probabilities of the other colors in terms of \( r \): - \( \text{Pr(pink)} = 2r \) - \( \text{Pr(brown)} = 2 \cdot 2r = 4r \) - \( \text{Pr(blue)} = 2 \cdot 4r = 8r \) - \( \text{Pr(green)} = 2 \cdot 8r = 16r \) Now we have: - \( \text{Pr(red)} = r \) - \( \text{Pr(pink)} = 2r \) - \( \text{Pr(brown)} = 4r \) - \( \text{Pr(blue)} = 8r \) - \( \text{Pr(green)} = 16r \) Next, we know that the total probability should equal 1, so we can set up the equation: \[ r + 2r + 4r + 8r + 16r = 1 \] This simplifies to: \[ 31r = 1 \] Thus, we find: \[ r = \frac{1}{31} \] Now we can calculate the probabilities: - \( \text{Pr(red)} = \frac{1}{31} \) - \( \text{Pr(pink)} = 2 \cdot \frac{1}{31} = \frac{2}{31} \) - \( \text{Pr(brown)} = 4 \cdot \frac{1}{31} = \frac{4}{31} \) - \( \text{Pr(blue)} = 8 \cdot \frac{1}{31} = \frac{8}{31} \) - \( \text{Pr(green)} = 16 \cdot \frac{1}{31} = \frac{16}{31} \) Therefore, the probabilities are: - Green: \( \frac{16}{31} \) - Blue: \( \frac{8}{31} \) - Brown: \( \frac{4}{31} \) - Pink: \( \frac{2}{31} \) - Red: \( \frac{1}{31} \) You can use this information to draw a spinner divided into these sections proportional to the calculated probabilities!

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