Question
upstudy study bank question image url

Sketch the graph of the function. \[ g(x)=\left\{\begin{array}{ll}x+1, & x \leq-4 \\ \frac{1}{2} x-5, & x>-4\end{array}\right. \] \[ \text {, } \]

Ask by Reeves Reed. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

To sketch the graph of the piecewise function: \[ g(x) = \begin{cases} x + 1, & \text{if } x \leq -4 \\ \frac{1}{2}x - 5, & \text{if } x > -4 \end{cases} \] 1. **Plot the left segment (\( x \leq -4 \)):** - Draw the line \( y = x + 1 \). - Include the point **(-4, -3)** with a solid dot. 2. **Plot the right segment (\( x > -4 \)):** - Draw the line \( y = \frac{1}{2}x - 5 \). - Exclude the point **(-4, -7)** with an open circle. 3. **Indicate the jump discontinuity** at \( x = -4 \) by the change in the line slopes. The graph consists of two straight lines meeting at \( x = -4 \) with a jump, showing the piecewise nature of the function.

Solution

To sketch the graph of the piecewise function: \[ g(x) = \begin{cases} x + 1, & \text{if } x \leq -4 \\ \frac{1}{2}x - 5, & \text{if } x > -4 \end{cases} \] follow these steps: ### 1. Analyze Each Piece Separately **a. For \( x \leq -4 \):** - **Function:** \( g(x) = x + 1 \) - **Type:** Straight line with a slope of **1** and a y-intercept at **(0, 1)**. - **Key Point at \( x = -4 \):** \[ g(-4) = -4 + 1 = -3 \] So, the point **(-4, -3)** is included in this segment. **b. For \( x > -4 \):** - **Function:** \( g(x) = \frac{1}{2}x - 5 \) - **Type:** Straight line with a slope of **½** and a y-intercept at **(0, -5)**. - **Behavior Near \( x = -4 \):** \[ \lim_{x \to -4^+} g(x) = \frac{1}{2}(-4) - 5 = -2 - 5 = -7 \] This means as \( x \) approaches **-4** from the right, \( g(x) \) approaches **-7**. However, the point **(-4, -7)** is **not** included in this segment since \( g(x) \) is defined as \( x > -4 \) here. ### 2. Determine Continuity at \( x = -4 \) - **Left Limit:** \( g(-4) = -3 \) - **Right Limit:** \( \lim_{x \to -4^+} g(x) = -7 \) Since the left and right limits at \( x = -4 \) are not equal, there is a **jump discontinuity** at this point. ### 3. Plotting the Graph **a. Plotting \( g(x) = x + 1 \) for \( x \leq -4 \):** - Draw a straight line with slope **1**. - Include the point **(-4, -3)** with a **solid dot** (since \( x = -4 \) is included). **b. Plotting \( g(x) = \frac{1}{2}x - 5 \) for \( x > -4 \):** - Draw a straight line with slope **½**. - Exclude the point **(-4, -7)** by placing an **open circle** at this point. **c. Additional Points for Clarity:** - For \( g(x) = \frac{1}{2}x - 5 \), when \( x = 0 \), \( g(0) = -5 \). Plot the point **(0, -5)**. - For \( g(x) = x + 1 \), when \( x = -5 \), \( g(-5) = -4 \). Plot the point **(-5, -4)**. ### 4. Graph Overview - **Left Segment (\( x \leq -4 \)):** A line rising to the right with a slope of **1**, passing through **(-4, -3)**. - **Right Segment (\( x > -4 \)):** A gentler line rising to the right with a slope of **½**, starting just above **x = -4** with an open circle at **(-4, -7)** and passing through **(0, -5)**. - **Discontinuity:** A visible jump from **(-4, -3)** to just above **(-4, -7)**. ### 5. Visual Representation While I can't provide a visual sketch here, you can visualize the graph based on the description: - **Left Line:** Starts from the left, increases with a slope of 1, and ends at **(-4, -3)** with a solid dot. - **Right Line:** Begins just to the right of **x = -4**, approaching **(-4, -7)** with an open circle, then continues with a slope of ½ through points like **(0, -5)**. Remember to clearly indicate the solid and open dots to show where each piece of the function is defined.

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Mind Expander

To get started with the graph of the function \( g(x) \), we can break it down into its two linear pieces. For \( x \leq -4 \), the function is a line with a slope of 1 and a y-intercept of 1, meaning it crosses the y-axis at \( (0, 1) \). For \( x > -4 \), the line has a slope of \( \frac{1}{2} \) and a y-intercept of -5, which crosses the y-axis at \( (0, -5) \). The point where the two pieces meet is crucial! At \( x = -4 \), both pieces should be evaluated to ensure a smooth transition. For the first part, \( g(-4) = -4 + 1 = -3 \), and for the second part, \( g(-4) = \frac{1}{2}(-4) - 5 = -2 - 5 = -7 \). This means there is a discontinuity at \( x = -4 \), as the left limit does not equal the right limit. Plotting these points will give you a graph with a line that ends in an open dot at \( (-4, -7) \) for \( x > -4 \), and a solid dot at \( (-4, -3) \) for \( x \leq -4 \).

Latest Pre Algebra Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy