Answer
To sketch the graph of the piecewise function:
\[
g(x) =
\begin{cases}
x + 1, & \text{if } x \leq -4 \\
\frac{1}{2}x - 5, & \text{if } x > -4
\end{cases}
\]
1. **Plot the left segment (\( x \leq -4 \)):**
- Draw the line \( y = x + 1 \).
- Include the point **(-4, -3)** with a solid dot.
2. **Plot the right segment (\( x > -4 \)):**
- Draw the line \( y = \frac{1}{2}x - 5 \).
- Exclude the point **(-4, -7)** with an open circle.
3. **Indicate the jump discontinuity** at \( x = -4 \) by the change in the line slopes.
The graph consists of two straight lines meeting at \( x = -4 \) with a jump, showing the piecewise nature of the function.
Solution
To sketch the graph of the piecewise function:
\[
g(x) =
\begin{cases}
x + 1, & \text{if } x \leq -4 \\
\frac{1}{2}x - 5, & \text{if } x > -4
\end{cases}
\]
follow these steps:
### 1. Analyze Each Piece Separately
**a. For \( x \leq -4 \):**
- **Function:** \( g(x) = x + 1 \)
- **Type:** Straight line with a slope of **1** and a y-intercept at **(0, 1)**.
- **Key Point at \( x = -4 \):**
\[
g(-4) = -4 + 1 = -3
\]
So, the point **(-4, -3)** is included in this segment.
**b. For \( x > -4 \):**
- **Function:** \( g(x) = \frac{1}{2}x - 5 \)
- **Type:** Straight line with a slope of **½** and a y-intercept at **(0, -5)**.
- **Behavior Near \( x = -4 \):**
\[
\lim_{x \to -4^+} g(x) = \frac{1}{2}(-4) - 5 = -2 - 5 = -7
\]
This means as \( x \) approaches **-4** from the right, \( g(x) \) approaches **-7**. However, the point **(-4, -7)** is **not** included in this segment since \( g(x) \) is defined as \( x > -4 \) here.
### 2. Determine Continuity at \( x = -4 \)
- **Left Limit:** \( g(-4) = -3 \)
- **Right Limit:** \( \lim_{x \to -4^+} g(x) = -7 \)
Since the left and right limits at \( x = -4 \) are not equal, there is a **jump discontinuity** at this point.
### 3. Plotting the Graph
**a. Plotting \( g(x) = x + 1 \) for \( x \leq -4 \):**
- Draw a straight line with slope **1**.
- Include the point **(-4, -3)** with a **solid dot** (since \( x = -4 \) is included).
**b. Plotting \( g(x) = \frac{1}{2}x - 5 \) for \( x > -4 \):**
- Draw a straight line with slope **½**.
- Exclude the point **(-4, -7)** by placing an **open circle** at this point.
**c. Additional Points for Clarity:**
- For \( g(x) = \frac{1}{2}x - 5 \), when \( x = 0 \), \( g(0) = -5 \). Plot the point **(0, -5)**.
- For \( g(x) = x + 1 \), when \( x = -5 \), \( g(-5) = -4 \). Plot the point **(-5, -4)**.
### 4. Graph Overview
- **Left Segment (\( x \leq -4 \)):** A line rising to the right with a slope of **1**, passing through **(-4, -3)**.
- **Right Segment (\( x > -4 \)):** A gentler line rising to the right with a slope of **½**, starting just above **x = -4** with an open circle at **(-4, -7)** and passing through **(0, -5)**.
- **Discontinuity:** A visible jump from **(-4, -3)** to just above **(-4, -7)**.
### 5. Visual Representation
While I can't provide a visual sketch here, you can visualize the graph based on the description:
- **Left Line:** Starts from the left, increases with a slope of 1, and ends at **(-4, -3)** with a solid dot.
- **Right Line:** Begins just to the right of **x = -4**, approaching **(-4, -7)** with an open circle, then continues with a slope of ½ through points like **(0, -5)**.
Remember to clearly indicate the solid and open dots to show where each piece of the function is defined.
Reviewed and approved by the UpStudy tutoring team
Explain
Simplify this solution