Question
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Solve the quadratic equation
If and are the solutions, then

Ask by Moran Hodges. in the United Arab Emirates
Nov 09,2024

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Tutor-Verified Answer

Answer

Solution

To solve the quadratic equation
we can rearrange it as follows:
This can be grouped into real and imaginary parts:
We can express as , where and are real numbers. Substituting into the equation gives:
Expanding :
Now substituting this into the equation:
This simplifies to:
For the equation to hold, both the real and imaginary parts must equal zero:
  1. Real part:
  2. Imaginary part:
Now we will solve these equations. From the second equation, we can express :
Substituting into the first equation:
This is quite complex, so let’s instead use the quadratic formula directly on the original equation. We can rewrite the equation in standard form:
This is a quadratic in :
Using the quadratic formula :
Here, , , and .
Calculating the discriminant:
Now we find . To do this, we can express it in polar form. The modulus is:
The argument is given by:
Thus, we can express in polar form as:
where .
Now, we can find :
Now substituting back into the quadratic formula:
Let and .
To find :
Using the property :
Thus, the final answer is:

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Extra Insights

To solve the quadratic equation
we can rewrite this as a standard quadratic equation in terms of :
Here, we identify , , and .
Now, we can apply the quadratic formula:
Calculating :
Now we calculate :
Next, we compute :
Now we find . To compute this, we express it in polar form. Let’s denote :
The argument is given by
Now, we need the angle corresponding to this, but it’s sufficient for us to find the square root:
Next, substituting back into the quadratic formula:
However, for our original question, we only need to calculate
A property of the roots of a quadratic is that
Thus, we compute:
and
Finally, we add these to find:
Thus, the final value is:

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