Using an electronic decibel meter, Monique measures the loudness of an acoustic guitar at a distance of 1 meter, and gets a reading of 65 decibels \( (d=65) \) Using the decibel formula, solve: \( 65=10 \log \left(\frac{P}{P_{0}}\right) \) to find the loudness ratio \( \frac{P}{P_{0}} \) Write your answer as a power of 10 like \( 10^{3} \) Next, using the same decibel meter and also from a distance of 1 meter, Monique measures an electric guitar at 100 decibels Using the decibel formula, solve: \( 100=10 \log \left(\frac{P}{P_{0}}\right) \) to find the loudness ratio \( \frac{P}{P_{0}} \) Write your answer as a power of 10 \( \frac{P}{P_{0}}=\square \) How much louder is the electric guitar? Using your answers for the loudness ratios: The electric guitar is Write your answer as a power of 10

9. Si dejamos caer al suelo una piedra cuya masa es de 4 kg desde una altura de 4 m , ¿Cuál es la energía cinética cuando ya ha recorrido la mitad de la caída a) hacia el suelo? b) CCual es la velocidad cuando alcanza el suelo?

5. Qué energía potencial posee un objeto con una masa de 6 kg a. A 4 m del suelo. b. A 6 m del suelo. 6. ¿A qué altura debería situarse una masa de 2 kg para poseer una energía

5.3 An aeroplane accelerates uniformly such that it goes from rest to \( 144 \mathrm{km.hr}^{-1} \) in 8 s . Calculate 5.3 .1 the acceleration of the aeroplane. 5.3 .2 the total distance that it has travelled in this time. Total for qu

3) Choose the correct alternative and rewrite the statement (i) The weight of a body on the earth's surface \( =\ldots \ldots . \). \( \begin{array}{llll}\text { (a) } \frac{G M m}{R} & \text { (b) } \frac{G M m}{R^{2}} & \text { (c) } G M m R^{2} & \text { (d) } \frac{G m}{R^{2}}\end{array} \)

QUESTION 6 (Start on a new page.) It has been established that the planet Omega has a moon and that the moon of Omega orbits the planet at a height, above the surface of Omega, which is equal to twice the radius of Omega. The mass of planet Omega is \( 3 \times 10^{15} \mathrm{~kg} \) and the mass of its moon is \( 1.5 \times 10^{13} \mathrm{~kg} \). The radius of the planet Omega is \( 8.5 \times 10^{6} \mathrm{~m} \) and the radius of its moon is \( 2.5 \times 10^{5} \mathrm{~m} \). 6.1 Determine the distance between the centre of the planet Omega and the centre of its moon.