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Home Question Bank Engineering Archive 2024 December 08

Engineering Questions from Dec 08,2024

Browse the Engineering Q&A Archive for Dec 08,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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3. A straight section of a proposed road, between chainages 3450 m and 3550 m , is to be constructed on ground having a transverse slope, which rises at 1 in 7 from left to right, at right angles to the proposed center line. The road is to be such that on any cross-section the formation level at the center line is to be lower than the existing level and the area of cut is equal to the area of fill. The road design includes the following specifications: - side slopes are to be 1 in 1 for cuttings and 1 in 3 for embankments - formation width \( =14.60 \mathrm{~m} \) - the center line of the road between chainage 3450 m and 3550 m is to be level Calculate the volume of cut required to form the road between chainages 3450 m and 3550 m . 4. A straight section of a proposed road having a formation width of 10.00 m is to be constructed as a cutting having side slopes of 1 in \( 2 . \mathrm{A} \) cross-section is to be taken at chainage 1225 m , where the depth of dig to the proposed formation level is to be 4.82 m . At this cross-section, the transverse slope at right angles to the proposed center line falls from left to right but changes at the proposed center line from a fall of 1 in 11 to a fall of 1 in 17 . Calculate the area of cut required at this cross-section. 1. A cutting is to be formed as part of a proposed road having a formation width of 7.30 m and side slopes of \( 1 \mathrm{in} 2 . \mathrm{A} \) cross-section is to be taken at chainage 2050 m , where the depth of dig to the proposed formation level is 10.89 m and the existing ground level is horizontal at right-angles to the proposed center line. Calculate the plan width and the area of cut required at this cross-section. 2. A cutting is to be formed on a section of a proposed road of formation width 10.00 m . The transverse slope at right- angles to the proposed center line is 1 in 8 and the existing ground levels at chainages \( 1750 \mathrm{~m}, 1800 \mathrm{~m} \) and 1850 m are 176.32 \( \mathrm{m}, 175.18 \mathrm{~m} \) and 174.87 m , respectively. The reduced level of the formation center line at chainage 1750 m is 173.65 m and the formation is to have a falling gradient of \( 4 \% \) from chainage 1750 m to chainage 1850 m . The side slopes are to be 1 in 3. Calculate the volume of cut required to form the cutting between chainages 1750 m and 1850 m . 5. An existing sewer at P is to be continued to Q and R on a falling gradient of 1 in 150 for plan distances of 27.12 m and 54.11 m consecutively, where the positions of \( \mathrm{P}, \mathrm{Q} \) and R are defined by wooden uprights. Given the following level observations, calculate the difference in level between the top of each upright and the position at which the top edge of each sight rail must be set at \( \mathrm{P}, \mathrm{Q} \) and R if a 2.5 m traveller is to be used. Level reading to staff on TBM on wall (RL 89.52 m\( ) 0.39 \mathrm{~m} \) Level reading to staff on top of upright at P 0.16 m Level reading to staff on top of upright at Q 0.35 m Level reading to staff on top of upright at R 1.17 m Level reading to staff on invert of existing sewer at P 2.84 m . All readings were taken from the same instrument position. 4. A cutting is to be formed on a section of a proposed road of formation width 10.00 m . The transverse slope at right-angles to the proposed centre line is 1 in 8 and the existing ground levels at chainages \( 1750 \mathrm{~m}, 1800 \mathrm{~m} \) and 1850 m are \( 176.32 \mathrm{~m}, 175.18 \) m and 174.87 m , respectively. The reduced level of the formation centre line at chainage 1750 m is 173.65 m and the formation is to have a falling gradient of \( 4 \% \) from chainage 1750 m to chainage 1850 m . The side slopes are to be 1 in 3. Calculate the volume of cut required to form the cutting between chainages 1750 m and 1850 m . If two Power Plants are linked together via a transmission line, explain with a diagram how both Plants can restore power in the event of a shutdown, and Plant A's Black- Starter is unavalable. 3. A straight section of a proposed road, between chainages 3450 m and 3550 m , is to be constructed on ground having a transverse slope, which rises at 1 in 7 from left to right, at right angles to the proposed centre line. The road is to be such that on any cross-section the formation level at the centre line is to be lower than the existing level and the area of cut is equal to the area of fill. The road design includes the following specifications: - side slopes are to be 1 in 1 for cuttings and 1 in 3 for embankments - formation width \( =14.60 \mathrm{~m} \) - the centre line of the road between chainage 3450 m and 3550 m is to be level Calculate the volume of cut required to form the road between chainages 3450 m and 3550 m The moist unit weight of the soil taken from the field is \( 1900 \mathrm{~kg} / \mathrm{m}^{3} \) and the moisture content is \( 11.5 \% \). The unit weight of solid soil is 2600 \( \mathrm{~kg} / \mathrm{m}^{3} \). 47. Compute the dry unit weight. \( \begin{array}{ll}\text { a. } 1804 \mathrm{~kg} / \mathrm{m}^{3} & \text { b. } 1904 \mathrm{~kg} / \mathrm{m}^{3} \\ \text { c. } 1704 \mathrm{~kg} / \mathrm{m}^{3} & \text { d. } 1604 \mathrm{~kg} / \mathrm{m}^{3} \\ \text { 48. Compute the void ratio. } \\ \begin{array}{ll}\text { a. } 0.626 & \text { b. } 0.526 \\ \text { c. } 0.426 & \text { d. } 0.326 \\ \text { 49. Compute the degree of saturation. } \\ \begin{array}{ll}\text { a. } 0.968 & \text { b. } 0.568\end{array} \\ \text { c. } 0.468 & \text { d. } 0.868\end{array}\end{array} \). SITUATION 9: A vat filled with paint is 9 m long. Its ends are in the form of trapezoid 3 m at the bottom and 5 m on the top. The vat is 4 m high and the specific gravity of paint is 0.8 . 50 . Compute the total weight of paint. \( \begin{array}{ll}\text { a. } 1960.2 \mathrm{kN} & \text { b. } 1130.1 \mathrm{kN} \\ \text { c. } 1340.1 \mathrm{kN} & \end{array} \) e moist unit weight of the soil taken from tt id is \( 1900 \mathrm{~kg} / \mathrm{m}^{3} \) and the moisture content \( .5 \% \). The unit weight of solid soil is 26 c \( / \mathrm{m}^{3} \). \( \begin{array}{ll}\text { Compute the dry unit weight. } 1804 \mathrm{~kg} / \mathrm{m}^{3} & \text { b. } 1904 \mathrm{~kg} / \mathrm{m}^{3} \\ \text { c. } 1704 \mathrm{~kg} / \mathrm{m}^{3} & \text { d. } 1604 \mathrm{~kg} / \mathrm{m}^{3}\end{array} \) \( \left\{\begin{array}{l}\text { Describe in details the types of: } \\ i \text { is In-situ tests. } \\ i i_{i} \text { Laborators test done on soil. }\end{array}\right. \)
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