Prove Rat: 1) \( \frac{\sin ^{2} y-\cos ^{2} y}{\cos ^{2} y+\sin y \cdot \cos y}=\tan y-1 \) 2) \( 2 \sin ^{2} 10^{\circ}-4 \cos ^{2} 70+2 \sin ^{2} 80^{\circ}-4 \cos ^{2} 20^{\circ}=-2\left(\right. \) without \( \begin{array}{c}\text { calcukator) } \\ \text { 3) } \frac{\cos ^{2} x+(1+\sin x)^{2}}{(1+\sin x) \cos x}=\frac{2}{\cos x} \\ \text { 4) } \cot ^{2} x-\tan ^{2} x=\frac{2 \cos ^{2} x-1}{\sin ^{2} x \cos ^{2} x}\end{array} \)
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Bonus Knowledge
To tackle the first equation, let’s rewrite the left side: \[ \frac{\sin^2 y - \cos^2 y}{\cos^2 y + \sin y \cdot \cos y} \] We can use the Pythagorean identity \(\sin^2 y + \cos^2 y = 1\) to simplify \(\sin^2 y - \cos^2 y\) to \(-(\cos^2 y - \sin^2 y)\). The right side, \(\tan y - 1\), can also be expressed in terms of sine and cosine. After substituting, simplifying, and using identities, you will find both sides balance out. For the second equation, start by converting the angles to a common reference and using trigonometric identities. Recall \(\cos(20^{\circ}) = \sin(70^{\circ})\) and \(\sin(80^{\circ}) = \cos(10^{\circ})\). After substituting and simplifying using identities, you will arrive at the result to be validated against the expression \(-2\). Both parts require careful manipulation of trigonometric identities and transformations, which can be quite engaging once you get into the rhythm of it! Feeling puzzled by the identities? Don't fret! Many common mistakes include forgetting the properties of sine and cosine, such as complementary angles, or misapplying angle addition formulas. Always double-check your steps for those little errors! For further practice, dive into trigonometric workbooks or online resources that have detailed solutions. They can illuminate tricky spots and deepen your understanding without a calculator!