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Aline intersects the \( x \)-axis at \( (-1,0) \) and is perpendicular to the line whose equation is \( y=-\frac{1}{5} x+9 \) \( \begin{array}{l}y=5 x+9 \\ y=-5 x+9 \\ y=-5 x+5 \\ y=5 x+5\end{array} \) \( \begin{array}{l}\text { ( }-5\end{array} \)

Ask by Park Blake. in the United States
Feb 03,2025

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Tutor-Verified Answer

Answer

The equation of line \( A \) is \( y = 5x + 5 \).

Solution

To determine the equation of the line \( A \) that intersects the \( x \)-axis at \( (-1, 0) \) and is perpendicular to the line \( y = -\frac{1}{5}x + 9 \), follow these steps: 1. **Find the Slope of the Given Line:** The equation of the given line is \( y = -\frac{1}{5}x + 9 \). The slope (\( m_1 \)) of this line is: \[ m_1 = -\frac{1}{5} \] 2. **Determine the Slope of the Perpendicular Line:** The slope (\( m_2 \)) of a line perpendicular to another is the negative reciprocal of the original slope. Therefore: \[ m_2 = -\frac{1}{m_1} = -\frac{1}{-\frac{1}{5}} = 5 \] 3. **Use the Point-Slope Form to Find the Equation of Line \( A \):** The line \( A \) has a slope of \( 5 \) and passes through the point \( (-1, 0) \). Using the point-slope form \( y - y_1 = m(x - x_1) \): \[ y - 0 = 5(x - (-1)) \\ y = 5(x + 1) \\ y = 5x + 5 \] 4. **Select the Correct Equation from the Options:** The correct equation of line \( A \) is: \[ y = 5x + 5 \] **Answer:** \( y = 5x + 5 \)

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The Deep Dive

To find the equation of line Aline, first note that the slope of the given line \( y = -\frac{1}{5}x + 9 \) is \( -\frac{1}{5} \). Since Aline is perpendicular to this line, its slope will be the negative reciprocal, which is \( 5 \). Using the point-slope form of the equation of a line \( y - y_1 = m(x - x_1) \) and the point where Aline intersects the x-axis \((-1, 0)\): \[ y - 0 = 5(x + 1) \] This simplifies to: \[ y = 5x + 5 \] So, Aline's equation is \( y = 5x + 5 \), hence the correct answer is the fourth option \( y = 5x + 5 \). Now, some fun facts! The concept of perpendicular lines isn’t just for geometry; it’s used in fields like physics where vectors are analyzed! For instance, that negative reciprocal relationship about slopes creates angles of \(90^\circ\), making it super useful for engineers designing structures to ensure integrity. And if you're ever wanting to brush up on lines, slopes, or geometry principles, dive into interactive geometry software or classic textbooks! There’s a wealth of resources out there, from the adventures of Euclid to modern math websites, each packed with illustrations and real-world connections to keep the learning engaging.

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