The voltage across a $$ 4.5-\mu \mathrm{F} $$ capacitor in a copying machine is zero. What is the voltage after 17 ms if current of 45 mA charges the capacitor? The voltage at $$ \mathrm{t}=17 \mathrm{~ms} $$ is $$ \square \mathrm{V} $$. (Type an integer or a decimal.)

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To find the voltage across the capacitor after 17 ms, we can use the formula for the charge on a capacitor:

$$ Q = CV $$

where:
- $$ Q $$ is the charge on the capacitor,
- $$ C $$ is the capacitance of the capacitor, and
- $$ V $$ is the voltage across the capacitor.

Given:
- Capacitance, $$ C = 4.5 \, \mu\text{F} = 4.5 \times 10^{-6} \, \text{F} $$
- Current, $$ I = 45 \, \text{mA} = 45 \times 10^{-3} \, \text{A} $$
- Time, $$ t = 17 \, \text{ms} = 17 \times 10^{-3} \, \text{s} $$

We can calculate the charge on the capacitor using the formula:

$$ Q = I \times t $$

Substitute the given values:

$$ Q = 45 \times 10^{-3} \times 17 \times 10^{-3} $$

Now, we can find the voltage across the capacitor using the formula:

$$ V = \frac{Q}{C} $$

Substitute the calculated value of $$ Q $$ and the given value of $$ C $$ to find the voltage after 17 ms.
Calculate the value by following steps:
- step0: Calculate:
  $$45\times 10^{-3}\times 17\times 10^{-3}$$
- step1: Multiply the terms:
  $$765\times 10^{-3}\times 10^{-3}$$
- step2: Multiply the terms:
  $$765\times 10^{-3-3}$$
- step3: Subtract the numbers:
  $$765\times 10^{-6}$$
- step4: Express with a positive exponent:
  $$765\times \frac{1}{10^{6}}$$
- step5: Rewrite the expression:
  $$5\times 153\times \frac{1}{10^{6}}$$
- step6: Rewrite the expression:
  $$5\times 153\times \frac{1}{5^{6}\times 2^{6}}$$
- step7: Reduce the numbers:
  $$153\times \frac{1}{5^{5}\times 2^{6}}$$
- step8: Multiply:
  $$\frac{153}{200000}$$
The charge on the capacitor is $$ 0.000765 \, \text{C} $$.

Now, we can find the voltage across the capacitor after 17 ms using the formula:

$$ V = \frac{Q}{C} $$

Substitute the calculated value of $$ Q $$ and the given value of $$ C $$ to find the voltage after 17 ms.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{0.000765}{\left(4.5\times 10^{-6}\right)}$$
- step1: Evaluate:
  $$\frac{0.000765}{4.5\times 10^{-6}}$$
- step2: Convert the expressions:
  $$\frac{\frac{153}{200000}}{4.5\times 10^{-6}}$$
- step3: Rewrite the expression:
  $$\frac{7.65\times 10^{-4}}{4.5\times 10^{-6}}$$
- step4: Separate the fraction:
  $$\frac{7.65}{4.5}\times \frac{10^{-4}}{10^{-6}}$$
- step5: Divide:
  $$1.7\times \frac{10^{-4}}{10^{-6}}$$
- step6: Divide:
  $$1.7\times 10^{-4-\left(-6\right)}$$
- step7: Evaluate:
  $$1.7\times 10^{2}$$
The voltage across the capacitor after 17 ms is $$ 170 \, \text{V} $$.
The voltage across the capacitor after 17 ms is 170 V.

The voltage across a capacitor in a copying machine is zero. What is the voltage after 17 ms if
current of 45 mA charges the capacitor?
The voltage at is . (Type an integer or a decimal.)

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The voltage across a capacitor in a copying machine is zero. What is the voltage after 17 ms if current of 45 mA charges the capacitor? The voltage at is . (Type an integer or a decimal.)