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P.O.W \#2 STATISTIC S AND PROBABILITY 1. The following cards are placed in a box. B 9 \( \square \) k 5 2 R z 8 W 3 If Joemar will pick a card without looking inside the box, find the probability that the card: a. contains the number 3 b. contains a letter c. is a number card d. is not a number card e. contains a shape

Ask by Stephens Fernandez. in the Philippines
Jan 27,2025

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Answer

- **a.** Probability of picking a card with the number 3: \( \frac{1}{9} \) - **b.** Probability of picking a letter: \( \frac{5}{9} \) - **c.** Probability of picking a number card: \( \frac{5}{9} \) - **d.** Probability of picking a non-number card: \( \frac{4}{9} \) - **e.** Probability of picking a card with a shape: \( \frac{1}{9} \)

Solution

Let's analyze each part of the problem step by step. ### **Given Cards in the Box:** 1. **B** (Letter) 2. **9 \( \square \) k** (Number: 9, Shape: Square, Letter: k) 3. **5** (Number) 4. **2** (Number) 5. **R** (Letter) 6. **z** (Letter) 7. **8** (Number) 8. **W** (Letter) 9. **3** (Number) There are **9** cards in total. --- ### **a. Probability that the card contains the number 3** - **Favorable Outcomes:** Only one card contains the number **3**. - **Total Possible Outcomes:** 9 \[ P(\text{contains } 3) = \frac{1}{9} \] --- ### **b. Probability that the card contains a letter** - **Cards with Letters:** - B - 9 \( \square \) **k** - R - **z** - **W** - **Number of Cards with Letters:** 5 \[ P(\text{contains a letter}) = \frac{5}{9} \] --- ### **c. Probability that the card is a number card** - **Number Cards:** - 9 \( \square \) k (contains number 9) - 5 - 2 - 8 - 3 - **Number of Number Cards:** 5 \[ P(\text{is a number card}) = \frac{5}{9} \] --- ### **d. Probability that the card is not a number card** - **Cards that are not number cards:** - B - 9 \( \square \) k (contains other elements but still a number card due to number 9) - R - z - W - **Number of Non-Number Cards:** 4 \[ P(\text{is not a number card}) = \frac{4}{9} \] --- ### **e. Probability that the card contains a shape** - **Cards with Shapes:** - 9 \( \square \) k (contains a square) - **Number of Cards with Shapes:** 1 \[ P(\text{contains a shape}) = \frac{1}{9} \] --- ### **Summary of Probabilities:** - **a.** \( \frac{1}{9} \) - **b.** \( \frac{5}{9} \) - **c.** \( \frac{5}{9} \) - **d.** \( \frac{4}{9} \) - **e.** \( \frac{1}{9} \)

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Beyond the Answer

To solve for the probabilities, let's first tally up the total number of cards in the box. There are 9 cards in total: B, 9, \( \square \), k, 5, 2, R, z, 8, and W, 3. a. **Probability of picking the card containing the number 3:** There is only 1 card with the number 3. So, the probability is \( \frac{1}{9} \). b. **Probability of picking a card that contains a letter:** The letters in the box are B, k, R, z, and W. That's a total of 5 letter cards. Therefore, the probability is \( \frac{5}{9} \). c. **Probability of picking a number card:** The number cards are 9, 5, 2, 8, and 3 — 5 cards total. So, the probability is \( \frac{5}{9} \). d. **Probability of not picking a number card:** Since we have 4 cards that aren't numbers (B, k, R, z, and W), the probability is \( \frac{4}{9} \). e. **Probability of picking a card that contains a shape:** There is only 1 card with a shape, \( \square \). Hence, the probability is \( \frac{1}{9} \). Now that we've calculated each of these probabilities, Joemar can confidently reach into the box!

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