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(a) Graph \( f(x)=2^{x}-4 \). (b) Find the zero of \( f(x) \). (c) Based on the graph, solve \( f(x)<0 \).

Ask by Beck Moran. in the United States
Jan 22,2025

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Answer

**(a) The graph of \( f(x) = 2^{x} - 4 \) is an exponential curve shifted downward by 4 units, passing through the point \( (2, 0) \). **(b) The zero of \( f(x) \) is at \( x = 2 \). **(c) \( f(x) < 0 \) for all real numbers \( x \) where \( x < 2 \).

Solution

Sure, let's tackle each part of the problem step by step. --- ### **(a) Graph of \( f(x) = 2^{x} - 4 \)** To graph the function \( f(x) = 2^{x} - 4 \), we'll analyze its key features: 1. **Base Function**: The base exponential function is \( 2^{x} \), which has the following characteristics: - **Y-intercept**: \( (0, 1) \) because \( 2^{0} = 1 \). - **Horizontal Asymptote**: \( y = 0 \) as \( x \to -\infty \). - **Growth**: Increases rapidly as \( x \) increases. 2. **Transformation**: The function \( 2^{x} - 4 \) shifts the base function **downward** by 4 units. - **New Y-intercept**: \( (0, 1 - 4) = (0, -3) \). - **Horizontal Asymptote**: \( y = -4 \). 3. **Plotting Points**: | \( x \) | \( 2^{x} \) | \( f(x) = 2^{x} - 4 \) | |---------|------------|------------------------| | -2 | 0.25 | -3.75 | | -1 | 0.5 | -3.5 | | 0 | 1 | -3 | | 1 | 2 | -2 | | 2 | 4 | 0 | | 3 | 8 | 4 | | 4 | 16 | 12 | 4. **Graph Description**: - Starts near the horizontal asymptote \( y = -4 \) for large negative \( x \) values. - Passes through the y-intercept at \( (0, -3) \). - Crosses the x-axis at \( x = 2 \) (zero of the function). - Increases rapidly as \( x \) becomes positive. *Since this is a text-based medium, please sketch the graph using the points above, ensuring the exponential growth and downward shift are represented.* --- ### **(b) Finding the Zero of \( f(x) \)** To find the zero of the function \( f(x) = 2^{x} - 4 \), set \( f(x) \) equal to zero and solve for \( x \): \[ 2^{x} - 4 = 0 \\ 2^{x} = 4 \] Since \( 4 \) is a power of \( 2 \), we can write: \[ 2^{x} = 2^{2} \\ x = 2 \] **Zero of \( f(x) \):** \( x = 2 \) *This means the graph of \( f(x) = 2^{x} - 4 \) crosses the x-axis at the point \( (2, 0) \).* --- ### **(c) Solving \( f(x) < 0 \) Based on the Graph** We need to determine the values of \( x \) for which \( f(x) = 2^{x} - 4 \) is less than zero: \[ 2^{x} - 4 < 0 \\ 2^{x} < 4 \] Again, recognizing that \( 4 = 2^{2} \): \[ 2^{x} < 2^{2} \] Since the base \( 2 \) is greater than 1, the inequality holds when the exponent is less than 2: \[ x < 2 \] **Solution:** All real numbers \( x \) such that \( x < 2 \). *Graphically, this corresponds to the portion of the graph below the x-axis, which occurs to the left of the vertical line \( x = 2 \).* --- ### **Summary** - **(a)** The graph of \( f(x) = 2^{x} - 4 \) is an exponential curve shifted downward by 4 units, with a y-intercept at \( (0, -3) \), a horizontal asymptote at \( y = -4 \), and passing through \( (2, 0) \). - **(b)** The zero of \( f(x) \) is at \( x = 2 \). - **(c)** \( f(x) < 0 \) for all real numbers \( x \) where \( x < 2 \).

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Bonus Knowledge

To graph \( f(x)=2^{x}-4 \), you start by plotting key points. When \( x = 0 \), \( f(0) = 2^0 - 4 = -3 \). When \( x = 2 \), \( f(2) = 2^2 - 4 = 0 \), which indicates one root. The graph approaches \( y = -4 \) as \( x \to -\infty \) and rises sharply as \( x \to +\infty \). To find the zero of \( f(x) \), set \( f(x) = 0 \): \( 2^x - 4 = 0 \) implies \( 2^x = 4 \). Hence, \( x = 2 \). This is the point where the graph intersects the x-axis. For \( f(x) < 0 \), the solution lies between \( -\infty \) and the zero. The graph indicates that \( f(x) < 0 \) when \( x < 2 \). Hence, the solution is \( x < 2 \). Curious about the behavior of exponential functions? They grow rapidly, and their graphs typically exhibit a smooth curve that never touches the x-axis for negative inputs, making them unique in their consistency and reliability. If you're interested in the practical uses of exponential functions, think about how they model real-life situations like population growth, radioactive decay, or even finance through compound interest! Understanding these applications can make algebra more relatable and exciting!

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