Aultiply \( (x-4)(2 x+3) \) using the FOIL method. Select the answer choice howing the FOIL method products. B. \( (2 x+3)+(x-4)(2 x)+(2 x)(3) \) C. \( (x)(2 x)+3(x)+(-4)(2 x)+(-4)(3) \) D. \( (x-4)(2 x)+(x-4)(3) \)

To use the FOIL method on \( (x-4)(2x+3) \), we take the First, Outer, Inner, and Last terms of each binomial. First, we multiply the First terms: \( x \cdot 2x = 2x^2 \). Next, we take the Outer terms: \( x \cdot 3 = 3x \). For the Inner terms, we have \( -4 \cdot 2x = -8x \), and lastly, the Last terms give us \( -4 \cdot 3 = -12 \). Combining these, the expression becomes \( 2x^2 + 3x - 8x - 12 \), which simplifies to \( 2x^2 - 5x - 12 \). Option C: \( (x)(2x) + 3(x) + (-4)(2x) + (-4)(3) \) shows the correct FOIL products, making it the correct choice!