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\( -8 x+5 \) and \( -5 x+10 \)

Ask by Powell Chavez. in the United States
Jan 23,2025

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Answer

The two lines \( y = -8x + 5 \) and \( y = -5x + 10 \) intersect at the point \( \left( -\frac{5}{3},\ \frac{55}{3} \right) \).

Solution

It looks like you've provided two linear expressions: 1. \( y = -8x + 5 \) 2. \( y = -5x + 10 \) If you're looking to **find the point of intersection** between these two lines, you can do so by setting the equations equal to each other and solving for \( x \). Here's how you can do it step-by-step: ### Step 1: Set the Equations Equal to Each Other \[ -8x + 5 = -5x + 10 \] ### Step 2: Solve for \( x \) First, get all the \( x \)-terms on one side and the constant terms on the other: \[ -8x + 5 = -5x + 10 \] \[ -8x + 5x = 10 - 5 \] \[ -3x = 5 \] \[ x = \frac{5}{-3} = -\frac{5}{3} \] ### Step 3: Substitute \( x \) Back into One of the Original Equations to Find \( y \) You can use either equation. Let's use \( y = -5x + 10 \): \[ y = -5\left(-\frac{5}{3}\right) + 10 \] \[ y = \frac{25}{3} + 10 \] \[ y = \frac{25}{3} + \frac{30}{3} = \frac{55}{3} \] ### Step 4: Write the Point of Intersection \[ \left( -\frac{5}{3},\ \frac{55}{3} \right) \] ### Visualization To better understand the intersection, here's a quick visualization of both lines: - **Line 1:** \( y = -8x + 5 \) - **Line 2:** \( y = -5x + 10 \) ![Graph of the two lines showing intersection point](https://i.imgur.com/yourimageurl.png) *(Replace with an actual graph if needed)* ### Summary - **Intersection Point:** \( \left( -\frac{5}{3},\ \frac{55}{3} \right) \) This is the point where both lines meet on the Cartesian plane. If you had a different question in mind regarding these expressions, feel free to provide more details!

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Extra Insights

Did you know that linear equations like \( -8x + 5 \) and \( -5x + 10 \) can be graphed on a coordinate plane to visualize how they interact? When plotted, the point where these two lines intersect represents the solution to the system of equations. This intersection point reveals the value of \( x \) and \( y \) that satisfies both equations simultaneously! If you're solving for where these two equations equal each other, remember to be careful with your algebra! A common mistake is to overlook signs or to miscalculate coefficients when isolating \( x \). Start by setting them equal to each other: \( -8x + 5 = -5x + 10 \). Then, simplify step by step, keeping an eye out for those pesky negative signs!

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