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Find an equation of the line where the planes \( Q \) and \( R \) intersect. Q: \( -2 x-3 y+4 z=1 \); \( R: x+y+z=1 \) Choose the correct answer below. A. An equation of the line is given by \( x=-\frac{1}{3}-3 t, y=-2 t, z=\frac{1}{4}+4 t \), where \( -\infty
Ask by Owen Ingram. in the United States
Feb 03,2025

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Answer

The equation of the line where planes \( Q \) and \( R \) intersect is: \[ x = 4 - 7t, \quad y = -3 + 6t, \quad z = t \] where \( t \) is any real number.

Solution

To find the equation of the line where the planes \( Q \) and \( R \) intersect, we'll follow these steps: 1. **Identify the Equations of the Planes:** - Plane \( Q \): \( -2x - 3y + 4z = 1 \) - Plane \( R \): \( x + y + z = 1 \) 2. **Find the Direction Vector of the Line:** The direction vector \( \mathbf{v} \) of the intersection line is perpendicular to the normals of both planes. The normal vectors are: - \( \mathbf{n}_Q = (-2, -3, 4) \) - \( \mathbf{n}_R = (1, 1, 1) \) The direction vector \( \mathbf{v} \) is given by the cross product \( \mathbf{n}_Q \times \mathbf{n}_R \): \[ \mathbf{v} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ -2 & -3 & 4 \\ 1 & 1 & 1 \\ \end{vmatrix} = (-7, 6, 1) \] 3. **Find a Point on the Line:** Solve the system of equations to find a specific point on both planes. Let's set \( z = 0 \): \[ \begin{cases} -2x - 3y = 1 \\ x + y = 1 \\ \end{cases} \] Solving these equations: - From the second equation: \( y = 1 - x \) - Substitute into the first equation: \[ -2x - 3(1 - x) = 1 \implies -2x - 3 + 3x = 1 \implies x = 4 \] - Then \( y = 1 - 4 = -3 \) So, one point on the line is \( (4, -3, 0) \). 4. **Write the Parametric Equations of the Line:** Using the direction vector and the point: \[ \begin{cases} x = 4 - 7t \\ y = -3 + 6t \\ z = t \\ \end{cases} \quad \text{where} \quad t \in \mathbb{R} \] **Therefore, the correct answer is:** **C. An equation of the line is given by \( x = 4 - 7 t \), \( y = -3 + 6 t \), \( z = t \), where \( -\infty < t < \infty \).**

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Bonus Knowledge

To find the intersection of the planes \( Q \) and \( R \), we can solve the system of equations formed by these planes. The planes intersect in a line, which can be represented parametrically. By eliminating one variable and expressing the others in terms of a parameter \( t \), we determine specific forms of \( x, y, z \). In terms of real-world application, the intersection of planes can represent the trajectory of objects in physics or engineering, such as the path of a missile or other projectiles that follow a certain trajectory determined by their initial conditions, impacted by multiple surfaces in their environment. For further reading, you might want to explore the concept of parametric equations and the geometry of lines and planes in 3D space. Understanding these topics can open doors to deeper insights into fields like computer graphics, robotics, and simulations, where spatial reasoning is key!

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