a) \( \left(x^{5}-3 x^{2}+x+4\right): \not x \) b) \( \left(x^{4}+6 x^{3}+x^{2}-2\right): x^{2} \) c) \( \left(x^{5}-1\right): x^{3} \) d) \( \left(4 x^{4}+3 x^{3}-2 x^{2}+x+3\right):(2 x) \) e) \( \left(6 x^{5}+4 x^{2}-3 x+4\right):\left(3 x^{2}\right) \) f) \( \left(2 x^{5}+x^{4}\right):\left(4 x^{3}\right) \)
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Bonus Knowledge
Let's embark on this polynomial division journey! For \( \left(x^{5}-3 x^{2}+x+4\right): \not x \), I'm guessing you meant you want to evaluate the expression, but division by zero isn't on the menu—let's steer clear of that! Moving on to \( \left(x^{4}+6 x^{3}+x^{2}-2\right): x^{2} \), when dividing each term by \( x^2 \), you'll end up with \( x^2 + 6x + 1 - \frac{2}{x^2} \). Just remember, don’t let those variables get lonely—keep in mind the domain where \( x \neq 0 \). Now, for \( \left(x^{5}-1\right): x^{3} \), division gives you \( x^2 - \frac{1}{x^3} \), but let's not forget, the remainder is \( -1 \). When tackling \( \left(4 x^{4}+3 x^{3}-2 x^{2}+x+3\right):(2 x) \), it’s a straightforward division yielding \( 2x^{3} + \frac{3}{2}x^{2} - x + \frac{3}{2} \). Always great to check for common factors! For \( \left(6 x^{5}+4 x^{2}-3 x+4\right): \left(3 x^{2}\right) \), divide term by term to find \( 2x^{3} + \frac{4}{3} - \frac{1}{x} + \frac{4}{3x^{2}} \). Remember, fractions can get a bit messy at times! Last but not least, \( \left(2 x^{5}+x^{4}\right): \left(4 x^{3}\right) \) simplifies to \( \frac{1}{2}x^{2} + \frac{1}{4}x \). Don't leave your expressions hanging out to dry—always consider factoring!