30- What is the sum? \[ 2 \frac{5}{12}+3 \frac{5}{4}=\ldots \ldots \ldots \ldots \]
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The Deep Dive
To find the sum of \( 2 \frac{5}{12} + 3 \frac{5}{4} \), we first convert the mixed numbers to improper fractions. For \( 2 \frac{5}{12} \): \[ 2 \frac{5}{12} = \frac{2 \times 12 + 5}{12} = \frac{24 + 5}{12} = \frac{29}{12} \] For \( 3 \frac{5}{4} \): \[ 3 \frac{5}{4} = \frac{3 \times 4 + 5}{4} = \frac{12 + 5}{4} = \frac{17}{4} \] Now, we need a common denominator to add these two fractions. The least common multiple of 12 and 4 is 12. We convert \(\frac{17}{4}\) to have a denominator of 12: \[ \frac{17}{4} = \frac{17 \times 3}{4 \times 3} = \frac{51}{12} \] Now we can add the fractions: \[ \frac{29}{12} + \frac{51}{12} = \frac{29 + 51}{12} = \frac{80}{12} \] We can simplify this fraction: \[ \frac{80}{12} = \frac{20}{3} \quad(\text{by dividing both numerator and denominator by 4}) \] To convert \(\frac{20}{3}\) back to a mixed number: \[ 20 \div 3 = 6 \quad \text{with a remainder of } 2 \] Thus, \[ \frac{20}{3} = 6 \frac{2}{3} \] The final answer is: \[ 6 \frac{2}{3} \]