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Which is equivalent to \( 54^{\frac{1}{4}} \) ? \( 2 \sqrt[4]{4} \) 4 16 \( 16 \sqrt[4]{4} \)

Ask by Wagner Mckenzie. in the United States
Feb 03,2025

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Answer

\(2 \sqrt[4]{4}\) is equivalent to \(54^{\frac{1}{4}}\).

Solution

To find the equivalent expression for \(54^{\frac{1}{4}}\), we need to understand that raising a number to the power of \(\frac{1}{4}\) is equivalent to taking the fourth root of that number. Given: \(54^{\frac{1}{4}}\) This can be rewritten as: \(\sqrt[4]{54}\) Now, let's compare this with the given options: 1. \(2 \sqrt[4]{4}\) 2. 4 3. 16 4. \(16 \sqrt[4]{4}\) Let's calculate the value of \(54^{\frac{1}{4}}\) and compare it with the given options: \(54^{\frac{1}{4}} = \sqrt[4]{54}\) Calculating the value: \(\sqrt[4]{54} \approx 3.5\) Now, let's compare this value with the given options: 1. \(2 \sqrt[4]{4} = 2 \times 2 = 4\) 2. 4 3. 16 4. \(16 \sqrt[4]{4} = 16 \times 2 = 32\) Therefore, the equivalent expression for \(54^{\frac{1}{4}}\) is \(2 \sqrt[4]{4}\), which is option 1.

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Bonus Knowledge

To find the equivalent of \( 54^{\frac{1}{4}} \), we can simplify it by first expressing 54 in terms of its prime factors. Since \( 54 = 2 \times 3^3 \), we can rewrite it as \( 54^{\frac{1}{4}} = (2 \times 3^3)^{\frac{1}{4}} = 2^{\frac{1}{4}} \times 3^{\frac{3}{4}} \). While this may not immediately seem helpful, understanding how to manipulate exponents is key in these types of problems. Now, let’s compare it with the options. Notably, we might estimate \( 54^{\frac{1}{4}} \) by simplifying the values directly. \( 54^{\frac{1}{4}} \approx 3.93 \), which suggests it is close to 4, but maintains slightly higher. Analyzing the options further, you would find that none of the other options neatly fit as \( 54^{\frac{1}{4}} \) is very much distinct from simple whole numbers. When dealing with fractional exponents, a common pitfall is miscalculating the basis of the exponent. Remember, \( x^{\frac{1}{n}} \) is not just about dividing but entails the entire radical root concept. Always recheck cases where you might cross two bases or confuse the overlay of roots.

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