In $$ \Delta \mathrm{FGH}, g=920 \mathrm{~cm}, h=950 \mathrm{~cm} $$ and $$ \angle \mathrm{F}=110^{\circ} $$. Find the area of $$ \Delta \mathrm{FGH} $$, to the nearest square centimeter.

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To find the area of $$ \Delta \mathrm{FGH} $$ with sides $$ g = 920 $$ cm, $$ h = 950 $$ cm, and angle $$ \angle \mathrm{F} = 110^\circ $$, we can use the formula for the area of a triangle when two sides and the included angle are known:

$$
\text{Area} = \frac{1}{2} \times g \times h \times \sin(\angle \mathrm{F})
$$

Plugging in the given values:

$$
\text{Area} = \frac{1}{2} \times 920 \, \text{cm} \times 950 \, \text{cm} \times \sin(110^\circ)
$$

First, calculate the sine of $$ 110^\circ $$:

$$
\sin(110^\circ) \approx 0.9396926
$$

Now, substitute this value back into the area formula:

$$
\text{Area} = \frac{1}{2} \times 920 \times 950 \times 0.9396926
$$

$$
\text{Area} = 437000 \times 0.9396926 \approx 410646 \, \text{cm}^2
$$

**Therefore, the area of $$ \Delta \mathrm{FGH} $$ is approximately $$ 410,646 $$ square centimeters.**

Answer: The area of ΔFGH is approximately 410 646 cm².
The area of $$ \Delta \mathrm{FGH} $$ is approximately $$ 410,646 $$ square centimeters.

In and . Find the area of , to the nearest square
centimeter.

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