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Which group of numbers is correctly ordered from least to greatest? \( -51,-24,-8,-7 \) \( 1,-2,3,-4 \) \( -3,-6,-37,-61 \) \( -11,-12,7,8 \)

Ask by Matthews Mcguire. in the United States
Jan 20,2025

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Answer

The correctly ordered group from least to greatest is \( -51, -24, -8, -7 \).

Solution

The correctly ordered group of numbers from least to greatest is: **\( -51, -24, -8, -7 \)** **Explanation:** Let's evaluate each group to determine if they are in ascending order (from least to greatest): 1. **\( -51, -24, -8, -7 \)** - \( -51 < -24 \) (True) - \( -24 < -8 \) (True) - \( -8 < -7 \) (True) **This group is correctly ordered.** 2. **\( 1, -2, 3, -4 \)** - \( 1 < -2 \) (False) **This group is not correctly ordered.** 3. **\( -3, -6, -37, -61 \)** - \( -3 < -6 \) (False) **This group is not correctly ordered.** 4. **\( -11, -12, 7, 8 \)** - \( -11 < -12 \) (False) **This group is not correctly ordered.** Only the first group \( -51, -24, -8, -7 \) is in the correct ascending order. **Answer:** \( -51, -24, -8, -7 \)

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When we look at the first group, \( -51,-24,-8,-7 \) is correctly ordered from least to greatest; each subsequent number is less negative or more positive. The second group, \( 1,-2,3,-4 \), is mixed up with positive and negative values. The third group, \( -3,-6,-37,-61 \), goes from least negative to most negative, so it’s indeed out of order! Lastly, \( -11,-12,7,8 \) has negatives first, but they aren’t in order either. So, hats off to the first group for getting it right! 🎉

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