Determine the interval(s) on which the following function is continuous. Then analyze the given limits. \( f(x)=\frac{e^{x}}{1-e^{6 x}} ; \lim _{x \rightarrow 0^{-}} f(x) ; \lim _{x \rightarrow 0^{+}} f(x) \) The function is continuous on the interval(s) (Simplify your answer. Type your answer in interval notation. Use a comma to separate answers as needed.
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The function \( f(x) = \frac{e^{x}}{1 - e^{6x}} \) is continuous wherever the denominator is not equal to zero. The expression \( 1 - e^{6x} = 0 \) leads us to find the points of discontinuity by solving for \( x \): \( e^{6x} = 1 \) gives \( 6x = 0 \), or \( x = 0 \). Thus, the function is continuous on the intervals \( (-\infty, 0) \) and \( (0, \infty) \). For the limits, as \( x \rightarrow 0^{-} \), the denominator approaches \( 1 - 1 = 0 \) from the negative side, thus \( f(x) \rightarrow -\infty \). As \( x \rightarrow 0^{+} \), the denominator similarly approaches zero from the positive side, leading to \( f(x) \rightarrow +\infty \).