Find functions $$ f(x) $$ and $$ g(x) $$ so the function $$ h(x)=\frac{4}{(2 x-3)^{2}} $$ can be expressed as $$ h(x)=f(g(x)) $$ Of(x)=$$ \frac{4}{x}, g(x)=2 x-3 $$ $$ O f(x)=2 x-3, g(x)=\frac{4}{x} $$ $$ O f(x)=2 x-3, g(x)=\frac{4}{x^{2}} $$ $$ O f(x)=\frac{4}{x^{2}}, g(x)=2 x-3 $$

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To express the function $$ h(x) = \frac{4}{(2x - 3)^2} $$ as $$ h(x) = f(g(x)) $$, let's evaluate each of the given options:

1. **Option 1: $$ f(x) = \frac{4}{x} $$, $$ g(x) = 2x - 3 $$**
   $$
   h(x) = f(g(x)) = \frac{4}{2x - 3}
   $$
   This does not match $$ \frac{4}{(2x - 3)^2} $$.

2. **Option 2: $$ f(x) = 2x - 3 $$, $$ g(x) = \frac{4}{x} $$**
   $$
   h(x) = f(g(x)) = 2\left(\frac{4}{x}\right) - 3 = \frac{8}{x} - 3
   $$
   This does not match $$ \frac{4}{(2x - 3)^2} $$.

3. **Option 3: $$ f(x) = 2x - 3 $$, $$ g(x) = \frac{4}{x^2} $$**
   $$
   h(x) = f(g(x)) = 2\left(\frac{4}{x^2}\right) - 3 = \frac{8}{x^2} - 3
   $$
   This does not match $$ \frac{4}{(2x - 3)^2} $$.

4. **Option 4: $$ f(x) = \frac{4}{x^2} $$, $$ g(x) = 2x - 3 $$**
   $$
   h(x) = f(g(x)) = \frac{4}{(2x - 3)^2}
   $$
   This exactly matches the given function $$ h(x) $$.

**Conclusion:**

The correct functions are:
$$
f(x) = \frac{4}{x^2}, \quad g(x) = 2x - 3
$$

**Answer:**
$$ f(x) = \dfrac{4}{\,x^{2}\,} $$ and $$ g(x) = 2\,x - 3 $$
$$ f(x) = \frac{4}{x^{2}} $$ and $$ g(x) = 2x - 3 $$

Find functions \( f(x) \) and \( g(x) \) so the function \( h(x)=\frac{4}{(2 x-3)^{2}} \) can be expressed as \( h(x)=f(g(x)) \) Of(x)=\( \frac{4}{x}, g(x)=2 x-3 \) \( O f(x)=2 x-3, g(x)=\frac{4}{x} \) \( O f(x)=2 x-3, g(x)=\frac{4}{x^{2}} \) \( O f(x)=\frac{4}{x^{2}}, g(x)=2 x-3 \)

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