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Evaluate the limit \( \lim _{x \rightarrow \infty} \frac{10 x^{3}-3 x^{2}-11 x}{9-11 x-4 x^{3}} \)

Ask by Morrison Chadwick. in the United States
Jan 29,2025

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Answer

The limit is \(-\dfrac{5}{2}\).

Solution

To evaluate the limit \[ \lim_{x \rightarrow \infty} \frac{10x^3 - 3x^2 - 11x}{9 - 11x - 4x^3}, \] we can analyze the behavior of the polynomial expressions as \( x \) approaches infinity. ### Step 1: Identify the Leading Terms In both the numerator and the denominator, the highest power of \( x \) will dominate the behavior of the expression as \( x \) becomes very large. - **Numerator:** The leading term is \( 10x^3 \). - **Denominator:** The leading term is \( -4x^3 \). ### Step 2: Simplify by Dividing by \( x^3 \) To make the comparison clearer, divide both the numerator and the denominator by \( x^3 \): \[ \frac{10x^3 - 3x^2 - 11x}{9 - 11x - 4x^3} = \frac{10 - \frac{3}{x} - \frac{11}{x^2}}{\frac{9}{x^3} - \frac{11}{x^2} - 4}. \] ### Step 3: Evaluate the Limit As \( x \) approaches infinity: - \( \frac{3}{x} \), \( \frac{11}{x^2} \), and \( \frac{9}{x^3} \) all approach 0. So, the expression simplifies to: \[ \frac{10}{-4} = -\frac{10}{4} = -\frac{5}{2}. \] ### Conclusion The limit is: \[ -\frac{5}{2}. \] **Answer:** \(-\dfrac{5}{2}\)

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To evaluate the limit \[ \lim _{x \rightarrow \infty} \frac{10 x^{3}-3 x^{2}-11 x}{9-11 x-4 x^{3}}, \] we first look at the leading terms of the numerator and denominator, since for \(x \to \infty\), these terms will dominate the behavior of the expression. The leading term in the numerator is \(10x^3\) and the leading term in the denominator is \(-4x^3\). Thus, we can rewrite the limit focusing on these leading terms: \[ \lim_{x \to \infty} \frac{10x^3 - 3x^2 - 11x}{9 - 11x - 4x^3} \approx \lim_{x \to \infty} \frac{10x^3}{-4x^3}. \] Simplifying this gives: \[ \lim_{x \to \infty} \frac{10}{-4} = -\frac{10}{4} = -\frac{5}{2}. \] Therefore, the limit is \[ \boxed{-\frac{5}{2}}. \]

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