Question

Describe how the graph of the radical function \( f(x) = \sqrt{x} \) changes when transformed to \( g(x) = \sqrt{x - 4} + 2 \).

Ask by Burgess Clark. in South Africa
Jan 23,2025

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Answer

The graph of \( f(x) = \sqrt{x} \) is shifted 4 units to the right and 2 units up to become \( g(x) = \sqrt{x - 4} + 2 \).

Solution

To understand how the graph of the radical function \( f(x) = \sqrt{x} \) changes when transformed to \( g(x) = \sqrt{x - 4} + 2 \), let's break down the transformations step by step. ### 1. **Start with the Basic Function:** \[ f(x) = \sqrt{x} \] - **Graph Characteristics:** - **Domain:** \( x \geq 0 \) - **Range:** \( y \geq 0 \) - **Key Point:** Starts at the origin \((0, 0)\) and increases to the right. ### 2. **Horizontal Shift (Inside the Square Root):** \[ h(x) = \sqrt{x - 4} \] - **Transformation:** The expression \( x - 4 \) inside the square root indicates a **horizontal shift**. - **Direction & Magnitude:** Shifts the graph **4 units to the right**. - **New Domain:** \( x - 4 \geq 0 \Rightarrow x \geq 4 \) - **New Key Point:** The starting point moves from \((0, 0)\) to \((4, 0)\). ![Horizontal Shift](https://i.imgur.com/3n7dM8H.png) *Graph of \( h(x) = \sqrt{x - 4} \): Shifted 4 units to the right.* ### 3. **Vertical Shift (Outside the Square Root):** \[ g(x) = \sqrt{x - 4} + 2 \] - **Transformation:** The \( +2 \) outside the square root indicates a **vertical shift**. - **Direction & Magnitude:** Shifts the graph **2 units upward**. - **New Range:** Since \( h(x) = \sqrt{x - 4} \) has a range of \( y \geq 0 \), adding 2 shifts the range to \( y \geq 2 \). - **New Key Point:** The starting point moves from \((4, 0)\) to \((4, 2)\). ![Vertical Shift](https://i.imgur.com/O4cRvhl.png) *Graph of \( g(x) = \sqrt{x - 4} + 2 \): Shifted 4 units to the right and 2 units upward.* ### 4. **Summary of Transformations:** - **Horizontal Shift:** 4 units **to the right**. - **Vertical Shift:** 2 units **upward**. ### 5. **Final Graph Characteristics of \( g(x) \):** - **Domain:** \( x \geq 4 \) - **Range:** \( y \geq 2 \) - **Key Point:** Starts at \((4, 2)\) and increases to the right. ### 6. **Visual Comparison:** - **Original Function \( f(x) = \sqrt{x} \):** ![Original Function](https://i.imgur.com/HTpCQMQ.png) - **Transformed Function \( g(x) = \sqrt{x - 4} + 2 \):** ![Transformed Function](https://i.imgur.com/O4cRvhl.png) ### 7. **Real-World Interpretation:** Imagine the square root function as the shape of a curve representing some real-world relationship (like the speed of a car increasing over time). Shifting it right by 4 units could represent a delay in the reaction time, and shifting it up by 2 units could indicate an initial boost or offset in the starting condition. --- **In Conclusion:** When transforming \( f(x) = \sqrt{x} \) to \( g(x) = \sqrt{x - 4} + 2 \), the graph undergoes two key transformations: 1. **Shifts 4 units to the right**, altering the starting point horizontally. 2. **Shifts 2 units upward**, raising the entire graph vertically. These transformations adjust both the position and the range of the original radical function, providing a new location and starting point for \( g(x) \).

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The transformation from \( f(x) = \sqrt{x} \) to \( g(x) = \sqrt{x - 4} + 2 \) involves two key changes: a horizontal shift and a vertical shift. The term \( x - 4 \) indicates that the graph of \( f(x) \) moves 4 units to the right, shifting the starting point from (0, 0) to (4, 0). The addition of 2 then shifts the entire graph upward by 2 units, bringing the new starting point to (4, 2). Visualizing these transformations helps! Picture the original graph of \( f(x) \), which resembles half of a sideways parabola beginning at the origin. After the transformations for \( g(x) \), the curve now starts at (4, 2) and continues to rise, maintaining its characteristic shape but offset from the original location. It's like taking a cozy chair (the graph of \( f(x) \)) and moving it to a sunnier spot in the room (the transformation), making it even more inviting!

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