Question
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If the odds in favor of Fast Leg winning a horse race are 9 to 7 and the first prize is \( \$ 112,000 \), what is the expected value of Fast Leg's winnings? The expected value is \( \$ \square \).

Ask by Ross Park. in the United States
Jan 23,2025

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Tutor-Verified Answer

Answer

The expected value of Fast Leg's winnings is \$63,000.

Solution

To calculate the expected value of Fast Leg's winnings, follow these steps: 1. **Determine the Probability of Winning:** The odds in favor of Fast Leg winning are 9 to 7. This means: \[ \text{Probability of winning} = \frac{9}{9 + 7} = \frac{9}{16} \] 2. **Determine the Probability of Losing:** \[ \text{Probability of losing} = 1 - \frac{9}{16} = \frac{7}{16} \] 3. **Calculate the Expected Value:** Assuming that if Fast Leg loses, the winnings are \$0, the expected value \( E \) is: \[ E = \left(\frac{9}{16}\right) \times \$112,000 + \left(\frac{7}{16}\right) \times \$0 = \frac{9}{16} \times \$112,000 \] \[ E = \frac{9 \times 112,000}{16} = \frac{1,008,000}{16} = \$63,000 \] **The expected value is \$63,000.**

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The Deep Dive

To calculate the expected value of Fast Leg's winnings, we need to consider both the likelihood of winning and losing. The odds of 9 to 7 mean that for every 16 races (9 wins + 7 losses), Fast Leg is expected to win 9 times. Therefore, the probability of winning is \( \frac{9}{16} \) and the probability of losing is \( \frac{7}{16} \). If Fast Leg wins, the winnings are \( \$ 112,000 \). If Fast Leg loses, the winnings are \( \$ 0 \). The expected value (EV) can be calculated as follows: \[ EV = \left( \text{Probability of Winning} \times \text{Winnings} \right) + \left( \text{Probability of Losing} \times \text{Losses} \right) \] \[ EV = \left( \frac{9}{16} \times 112,000 \right) + \left( \frac{7}{16} \times 0 \right) = \left( \frac{9 \times 112,000}{16} \right) \] \[ EV = \frac{1,008,000}{16} = 63,000 \] Thus, the expected value of Fast Leg's winnings is \( \$ 63,000 \).

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