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а. \( 4 x+3(2 x-7)+11 \) в. \( -2(2 x-8)+9(x-1) \) д. \( -8(3 c-6)+4(7 c-10)-8 \)

Ask by Simpson Ward. in Mongolia
Jan 22,2025

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а. \(10x - 10\) в. \(5x + 7\) д. \(4c\)

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Для выражения \( 4 x + 3(2 x - 7) + 11 \) сначала раскроем скобки: \( 4x + 6x - 21 + 11 \). Затем объединим похожие слагаемые: \( 10x - 10 \). Для второго выражения \( -2(2x - 8) + 9(x - 1) \) также раскроем скобки: \( -4x + 16 + 9x - 9 \). Объединив, получаем \( 5x + 7 \). Теперь давайте раскроем третье выражение \( -8(3c - 6) + 4(7c - 10) - 8 \). Раскрываем: \( -24c + 48 + 28c - 40 - 8 \). Объединяя, мы получаем \( 4c + 0 \), или просто \( 4c \).

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