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In \( \Delta \mathrm{JKL}, j=820 \) inches, \( k=530 \) inches and \( l=960 \) inches. Find the measure of \( \angle \mathrm{K} \) to the nearest degree.

Ask by Macdonald Medina. in the United States
Jan 23,2025

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Answer

The measure of \( \angle \mathrm{K} \) is approximately 33 degrees.

Solution

To find the measure of \( \angle \mathrm{K} \) in \( \Delta \mathrm{JKL} \) with sides \( j = 820 \) inches, \( k = 530 \) inches, and \( l = 960 \) inches, we can use the Law of Cosines. The Law of Cosines relates the lengths of the sides of a triangle to the cosine of one of its angles: \[ \cos K = \frac{j^2 + l^2 - k^2}{2jl} \] Let's compute each part step by step: 1. **Calculate the squares of the sides:** \[ j^2 = 820^2 = 672,400 \] \[ l^2 = 960^2 = 921,600 \] \[ k^2 = 530^2 = 280,900 \] 2. **Substitute these values into the formula:** \[ \cos K = \frac{672,400 + 921,600 - 280,900}{2 \times 820 \times 960} \] \[ \cos K = \frac{1,313,100}{1,574,400} \approx 0.8340 \] 3. **Find the angle \( K \) by taking the arccosine of 0.8340:** \[ K = \arccos(0.8340) \approx 33^\circ \] **Therefore, the measure of \( \angle \mathrm{K} \) is approximately 33 degrees.** **Answer:** \( \angle \mathrm{K} \) is approximately 33 degrees.

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To find the measure of \( \angle K \) in \( \Delta JKL \), we can use the Law of Cosines, which states that for any triangle with sides \( a \), \( b \), and \( c \), and the corresponding opposite angles \( A \), \( B \), and \( C \): \[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) \] In this case, let \( j = 820 \) inches, \( k = 530 \) inches, and \( l = 960 \) inches. We are trying to find \( \angle K \), which is opposite side \( l \). Rearranging the Law of Cosines for \( \angle K \): \[ l^2 = j^2 + k^2 - 2jk \cdot \cos(K) \] Substituting the values we have: \[ 960^2 = 820^2 + 530^2 - 2 \cdot 820 \cdot 530 \cdot \cos(K) \] Calculating: \[ 921600 = 672400 + 280900 - 2 \cdot 820 \cdot 530 \cdot \cos(K) \] \[ 921600 = 953300 - 871200 \cdot \cos(K) \] Rearranging gives: \[ 871200 \cdot \cos(K) = 953300 - 921600 \] \[ 871200 \cdot \cos(K) = 31600 \] Dividing by 871200: \[ \cos(K) = \frac{31600}{871200} \approx 0.0362 \] Now find \( \angle K \): \[ K \approx \cos^{-1}(0.0362) \] Using a calculator: \[ K \approx 88.9^\circ \] Rounding to the nearest degree, we get: \[ \angle K \approx 89^\circ \]

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