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Simplify. \[ \frac{u-8}{u^{2}-16 u+64} \]

Ask by West Mitchell. in the United States
Jan 27,2025

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Answer

\[ \frac{1}{u - 8} \]

Solution

To simplify the expression: \[ \frac{u - 8}{u^{2} - 16u + 64} \] **Step 1: Factor the Denominator** First, factor the quadratic expression in the denominator: \[ u^2 - 16u + 64 \] This quadratic can be written as a perfect square: \[ u^2 - 16u + 64 = (u - 8)^2 \] **Step 2: Simplify the Expression** Now, substitute the factored form back into the original expression: \[ \frac{u - 8}{(u - 8)^2} \] Simplify by canceling out one \((u - 8)\) from the numerator and the denominator: \[ \frac{1}{u - 8} \] **Final Answer:** \[ \boxed{\dfrac{1}{\,u-8\,}} \]

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The Deep Dive

To simplify the expression \(\frac{u-8}{u^{2}-16u+64}\), we start by factoring the denominator. Notice that the denominator can be rewritten: \[ u^{2} - 16u + 64 = (u - 8)^{2} \] Now, we substitute this back into the expression: \[ \frac{u-8}{(u - 8)^{2}} \] Next, we can simplify by canceling one \(u - 8\) from the numerator and the denominator: \[ \frac{1}{u - 8} \quad \text{for } u \neq 8 \] Thus, the simplified expression is: \[ \frac{1}{u - 8} \]

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