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(13) \( \frac{8 d^{2}+24 d}{20} \div(d+3)^{2} \)

Ask by Kelley Chan. in the United States
Feb 03,2025

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Tutor-Verified Answer

Answer

The simplified form of the expression is \( \frac{2d}{5(d + 3)} \).

Solution

To simplify the expression: \[ \frac{8d^{2} + 24d}{20} \div (d + 3)^{2} \] Follow these steps: 1. **Rewrite the Division as Multiplication:** Dividing by \((d + 3)^2\) is the same as multiplying by \(\frac{1}{(d + 3)^2}\): \[ \frac{8d^{2} + 24d}{20} \times \frac{1}{(d + 3)^2} \] 2. **Factor the Numerator:** Factor out the greatest common factor (GCF) from \(8d^{2} + 24d\): \[ 8d^{2} + 24d = 8d(d + 3) \] So, the expression becomes: \[ \frac{8d(d + 3)}{20} \times \frac{1}{(d + 3)^2} \] 3. **Simplify the Expression:** Combine the fractions: \[ \frac{8d(d + 3)}{20(d + 3)^2} \] Cancel out one \((d + 3)\) term from the numerator and denominator: \[ \frac{8d}{20(d + 3)} \] 4. **Reduce the Fraction:** Simplify \(\frac{8}{20}\) by dividing both numerator and denominator by 4: \[ \frac{2}{5} \] So, the expression simplifies to: \[ \frac{2d}{5(d + 3)} \] **Final Simplified Form:** \[ \boxed{\dfrac{2d}{5(d+3)}} \]

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Beyond the Answer

To simplify the expression \( \frac{8 d^{2}+24 d}{20} \div(d+3)^{2} \), we first simplify the numerator. Notice that \( 8d^{2} + 24d \) can be factored as \( 8d(d+3) \). So we rewrite the expression as follows: \[ \frac{8d(d + 3)}{20} \div (d + 3)^{2} \] Next, dividing by \( (d + 3)^{2} \) is equivalent to multiplying by its reciprocal: \[ = \frac{8d(d + 3)}{20} \cdot \frac{1}{(d + 3)^{2}} \] Now, we can cancel one \( (d + 3) \) factor from the numerator: \[ = \frac{8d}{20(d + 3)} \] Finally, we simplify \( \frac{8d}{20} \): \[ = \frac{2d}{5(d + 3)} \] So, the final simplified form of the original expression is: \[ \frac{2d}{5(d + 3)} \]

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