Question Solve the system by substitution. \[ \begin{aligned} x & =-4 y-15 \\ 2 x+10 y & =8\end{aligned} \]

To solve the system by substitution, we can start with the first equation, \( x = -4y - 15 \). Next, we substitute this expression for \( x \) into the second equation: \[ 2(-4y - 15) + 10y = 8 \] Now, distribute the 2: \[ -8y - 30 + 10y = 8 \] Combine like terms: \[ 2y - 30 = 8 \] Now, isolate \( y \) by adding 30 to both sides: \[ 2y = 38 \] Dividing both sides by 2 gives: \[ y = 19 \] Now that we have \( y \), we can substitute it back into the first equation to find \( x \): \[ x = -4(19) - 15 \] Calculating this: \[ x = -76 - 15 = -91 \] Thus, the solution to the system is \( (x, y) = (-91, 19) \).