\( 1 \Leftarrow \left\lvert\, \begin{array}{l}\text { Solve for the unknown in the equation. } \\ 4 B+4 B-5=19\end{array} \quad \begin{array}{l}B=\square \text { (Simplify your answer.) }\end{array}\right. \)

To solve for \( B \) in the equation: \[ 4B + 4B - 5 = 19 \] **Step 1:** Combine like terms. \[ 4B + 4B = 8B \] So the equation becomes: \[ 8B - 5 = 19 \] **Step 2:** Add 5 to both sides to isolate the term with \( B \). \[ 8B = 19 + 5 \] \[ 8B = 24 \] **Step 3:** Divide both sides by 8 to solve for \( B \). \[ B = \frac{24}{8} \] \[ B = 3 \] **Final Answer:** \[ B = 3 \]