Question
Kerjakan soal-soal berikut dengan benar!
(. Nyatakan dalam perbandingan trigonom
\( \begin{array}{ll}\text { a. } \sin 165^{\circ} & \text { d. } \sec \left(-55

Kerjakan soal-soal berikut dengan benar! (. Nyatakan dalam perbandingan trigonom \( \begin{array}{ll}\text { a. } \sin 165^{\circ} & \text { d. } \sec \left(-55^{\circ}\right) \\ \text { b. } \cos 1.240^{\circ} & \text { e. } \operatorname{cosec} 505^{\circ} \\ \text { c. } \tan 340^{\circ} & \text { f. } \operatorname{cotan} 215^{\circ} \\ \text { Jawab: }\end{array} \) Tentukan nilai-nilai perbandingan trigonom pada titik berikut! a. A(5, 12)

Ask by Bernard Higgins.
Feb 05,2025 03:01

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a. \(\sin 165^{\circ} = \sin 15^{\circ}\) b. \(\cos 1.240^{\circ}\) (tidak dapat disederhanakan lebih lanjut) c. \(\tan 340^{\circ} = -\tan 20^{\circ}\) d. \(\sec(-55^{\circ}) = \sec 55^{\circ}\) e. \(\cosec 505^{\circ} = \cosec 145^{\circ}\) f. \(\cotan 215^{\circ} = \cot 35^{\circ}\) --- Titik A(5, 12): \[ \begin{align*} \sin \theta &= \frac{5}{13} \\ \cos \theta &= \frac{12}{13} \\ \tan \theta &= \frac{5}{12} \\ \sec \theta &= \frac{13}{12} \\ \cosec \theta &= \frac{13}{5} \\ \cot \theta &= \frac{12}{5} \\ \end{align*} \]

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Mari kita ulas beberapa fakta menarik tentang soal-soal trigonometri ini! Untuk \( \sin 165^{\circ} \), kita bisa menganalisis sudut tersebut. Sudut 165 derajat terletak di kuadran kedua, di mana sinus positif. Dengan menggunakan identitas sinus sudut, kita dapat menuliskan \( \sin 165^{\circ} = \sin(180^{\circ} - 15^{\circ}) = \sin 15^{\circ} \). Dengan perhitungan lebih lanjut, kita akan menemukan bahwa nilainya bisa didapatkan dari rumus sinus sudut kecil. Sekarang, mengenai titik A(5, 12), kita bisa menghitung nilai perbandingan trigonometrinya dengan menggunakan hubungan segitiga. Panjang hipotenusa dapat ditemukan menggunakan teorema Pythagoras: \( r = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \). Dengan ini, kita bisa menghitung nilai \( \sin A = \frac{y}{r} = \frac{12}{13} \), \( \cos A = \frac{x}{r} = \frac{5}{13} \), dan seterusnya. Seru, kan, mempelajari sifat-sifat segitiga dengan cara ini?

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