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Is this a Function? \( D: 3,6,6,12,18 \) \( R: 7,5,10,9,10 \)

Ask by Floyd Olson. in Guam
Jan 27,2025

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Answer

The relation is not a function because the input **6** is paired with both **5** and **10**.

Solution

To determine whether the given relation is a function, let's analyze the provided sets: - **Domain (D):** 3, 6, 6, 12, 18 - **Range (R):** 7, 5, 10, 9, 10 ### Understanding Functions A **function** is a relation where **each element in the domain is associated with exactly one element in the range**. This means: 1. **Every input has an output:** No element in the domain is left without a corresponding element in the range. 2. **No input has multiple outputs:** Each element in the domain is paired with one and only one element in the range. ### Analyzing the Given Relation Let's pair the elements of the domain (D) with the range (R) based on their positions: 1. **3 → 7** 2. **6 → 5** 3. **6 → 10** 4. **12 → 9** 5. **18 → 10** ### Identifying Issues - **Repeated Input with Different Outputs:** The number **6** appears **twice** in the domain but is associated with two **different** outputs: **5** and **10**. This violates the second rule of functions, where each input should map to only one output. ### Conclusion Since the input **6** is associated with two different outputs (**5** and **10**), the given relation **is not a function**. **Final Answer:** No. The input value 6 is paired with both 5 and 10, so each input does not have exactly one output.

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To determine if the set of ordered pairs defines a function, we need to check if every element in the domain (D) corresponds to exactly one element in the range (R). In your case, the domain contains the values \(3, 6, 6, 12, 18\). Notice that \(6\) appears twice in the domain. If both instances of \(6\) were associated with different values in the range (like \(5\) and \(10\)), it wouldn't be a function, since a single input cannot yield multiple outputs. Next, since \(10\) is repeated in the range, it might look harmless—but paired with \(6\) being a potential problem, we're left pondering. Ultimately, here, because \(6\) appears twice without a unique output, this collection does not define a function! Now, imagine you're the mathematician about to declare this set a function! Rule number one: be vigilant. Always check for duplicates in the left side of your ordered pairs, as it can lead to function fail. To avoid this situation in the future, write down each unique input and its corresponding output. Mapping them out can help prevent confusion and keep your function-sensing skills sharp!

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