Question
b) \( 4713-292+250= \) c) \( 13420+118065-12 \)
Ask by Bernard Tyler. in South Africa
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
**b) \( 4713 - 292 + 250 = 4671 \)
c) \( 13420 + 118065 - 12 = 131,\!473 \)**
Solution
Sure, let's solve each problem step by step.
---
### **b) \( 4713 - 292 + 250 \)**
**Step 1:** Subtract 292 from 4713.
\[
4713 - 292 = 4421
\]
**Step 2:** Add 250 to the result.
\[
4421 + 250 = 4671
\]
**Final Answer:** \( 4671 \)
---
### **c) \( 13420 + 118065 - 12 \)**
**Step 1:** Add 13,420 to 118,065.
\[
13420 + 118065 = 131,485
\]
**Step 2:** Subtract 12 from the result.
\[
131,485 - 12 = 131,473
\]
**Final Answer:** \( 131,\!473 \)
---
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To solve \( 4713 - 292 + 250 \), first subtract: \( 4713 - 292 = 4421 \). Then, add \( 250 \): \( 4421 + 250 = 4671 \). So, the final answer is \( 4671 \). For \( 13420 + 118065 - 12 \), start by adding: \( 13420 + 118065 = 131485 \). Then, subtract \( 12 \): \( 131485 - 12 = 131473 \). Thus, the final answer is \( 131473 \).