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b) \( 4713-292+250= \) c) \( 13420+118065-12 \)

Ask by Bernard Tyler. in South Africa
Feb 03,2025

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Answer

**b) \( 4713 - 292 + 250 = 4671 \) c) \( 13420 + 118065 - 12 = 131,\!473 \)**

Solution

Sure, let's solve each problem step by step. --- ### **b) \( 4713 - 292 + 250 \)** **Step 1:** Subtract 292 from 4713. \[ 4713 - 292 = 4421 \] **Step 2:** Add 250 to the result. \[ 4421 + 250 = 4671 \] **Final Answer:** \( 4671 \) --- ### **c) \( 13420 + 118065 - 12 \)** **Step 1:** Add 13,420 to 118,065. \[ 13420 + 118065 = 131,485 \] **Step 2:** Subtract 12 from the result. \[ 131,485 - 12 = 131,473 \] **Final Answer:** \( 131,\!473 \) --- If you have any more questions or need further clarification, feel free to ask!

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To solve \( 4713 - 292 + 250 \), first subtract: \( 4713 - 292 = 4421 \). Then, add \( 250 \): \( 4421 + 250 = 4671 \). So, the final answer is \( 4671 \). For \( 13420 + 118065 - 12 \), start by adding: \( 13420 + 118065 = 131485 \). Then, subtract \( 12 \): \( 131485 - 12 = 131473 \). Thus, the final answer is \( 131473 \).

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