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1 There are 11 students running a relay race that is 2 mi long. Each student runs approximately \( \frac{2}{11} \mathrm{mi} \). The course has a marker every 0.1 mi . Between which two markers does the second student finish? Show your work.

Ask by Campbell Mathis. in the United States
Feb 03,2025

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Answer

The second student finishes between Marker 1 and Marker 2.

Solution

To determine between which two markers the second student finishes, we can follow these steps: 1. **Calculate the distance run by the second student.** Each student runs approximately \( \frac{2}{11} \) miles. Therefore, the distance run by the second student is: \[ d_2 = \frac{2}{11} \text{ mi} \] 2. **Convert the distance into a decimal.** We can calculate \( d_2 \) as follows: \[ d_2 = \frac{2}{11} \approx 0.181818 \text{ mi} \] 3. **Identify the markers on the course.** The course has markers every 0.1 miles. The markers are located at: - Marker 1: 0.1 mi - Marker 2: 0.2 mi - Marker 3: 0.3 mi - Marker 4: 0.4 mi - Marker 5: 0.5 mi - Marker 6: 0.6 mi - Marker 7: 0.7 mi - Marker 8: 0.8 mi - Marker 9: 0.9 mi - Marker 10: 1.0 mi - Marker 11: 1.1 mi - Marker 12: 1.2 mi - Marker 13: 1.3 mi - Marker 14: 1.4 mi - Marker 15: 1.5 mi - Marker 16: 1.6 mi - Marker 17: 1.7 mi - Marker 18: 1.8 mi - Marker 19: 1.9 mi - Marker 20: 2.0 mi 4. **Determine between which markers the second student finishes.** Since \( d_2 \approx 0.181818 \) miles, we can see that this distance is greater than 0.1 miles (Marker 1) but less than 0.2 miles (Marker 2). Therefore, the second student finishes between Marker 1 and Marker 2. In conclusion, the second student finishes between Marker 1 and Marker 2.

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To find out where the second student finishes, we first determine the distance that the second student runs. Since each student runs approximately \( \frac{2}{11} \) miles, we calculate the total distance covered by the first student as well before the second student starts running. The first student runs \( \frac{2}{11} \text{ mi} \). Therefore, the second student will start running after the first student has finished their leg of the race. Here's how you can calculate it step by step: 1. **Distance the first student runs:** \[ D_1 = \frac{2}{11} \text{ mi} \] 2. **Distance covered by the first student before the second student starts:** \[ D_1 = 0.1818 \text{ mi} \, (\text{approximately}) \] 3. **Distance the second student runs:** The second student also runs \( \frac{2}{11} \text{ mi} = 0.1818 \text{ mi} \). 4. **Total distance covered by the first and second students:** \[ D_{\text{total}} = D_1 + D_2 = 0.1818 \text{ mi} + 0.1818 \text{ mi} = 0.3636 \text{ mi} \] Now, we need to determine between which two markers this distance lies. The course has a marker every 0.1 miles: - The markers are at: - 0.0 mi - 0.1 mi - 0.2 mi - 0.3 mi - 0.4 mi The total distance covered by the second student is approximately 0.3636 miles, which is just shy of the 0.4-mile marker. Therefore, the second student finishes between the 0.3-mile marker and the 0.4-mile marker.

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