13. [-/6.66 Points] DETAILS MY NOTES AUFMODMATH2 22.5A.008. A coin is tossed four times. What is the probability that the outcomes of the tosses are exactly in the order THTH?

Question

UpStudy AI · Accepted Answer

To find the probability of getting the specific sequence THTH when tossing a coin four times, we can follow these steps:

1. **Identify the total number of outcomes**: When a coin is tossed, there are 2 possible outcomes (Heads or Tails). Therefore, for four tosses, the total number of outcomes is given by:
   $$
   2^n
   $$
   where $$ n $$ is the number of tosses.

2. **Calculate the total outcomes**: In this case, $$ n = 4 $$:
   $$
   2^4 = 16
   $$

3. **Identify the favorable outcome**: The specific sequence THTH is just one of the 16 possible outcomes.

4. **Calculate the probability**: The probability $$ P $$ of getting the sequence THTH is given by the ratio of the number of favorable outcomes to the total number of outcomes:
   $$
   P = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{1}{16}
   $$

Thus, the probability of getting the outcomes THTH when tossing a coin four times is $$ \frac{1}{16} $$.
The probability of getting the sequence THTH when tossing a coin four times is $$ \frac{1}{16} $$.

[-/6.66 Points] DETAILS MY NOTES AUFMODMATH2 22.5A.008.
A coin is tossed four times. What is the probability that the outcomes of the tosses are exactly in the order THTH?

Upstudy AI Solution

Answer

Solution

The Deep Dive

Related Questions

Latest Probability Questions