13. [-/6.66 Points] DETAILS MY NOTES AUFMODMATH2 22.5A.008. A coin is tossed four times. What is the probability that the outcomes of the tosses are exactly in the order THTH?

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To find the probability of getting the specific sequence THTH when tossing a coin four times, we can follow these steps:

1. **Identify the total number of outcomes**: When a coin is tossed, there are 2 possible outcomes (Heads or Tails). Therefore, for four tosses, the total number of outcomes is given by:
   $$
   2^n
   $$
   where $$ n $$ is the number of tosses.

2. **Calculate the total outcomes**: In this case, $$ n = 4 $$:
   $$
   2^4 = 16
   $$

3. **Identify the favorable outcome**: The specific sequence THTH is just one of the 16 possible outcomes.

4. **Calculate the probability**: The probability $$ P $$ of getting the sequence THTH is given by the ratio of the number of favorable outcomes to the total number of outcomes:
   $$
   P = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{1}{16}
   $$

Thus, the probability of getting the outcomes THTH when tossing a coin four times is $$ \frac{1}{16} $$.
The probability of getting the sequence THTH when tossing a coin four times is $$ \frac{1}{16} $$.

[-/6.66 Points] DETAILS MY NOTES AUFMODMATH2 22.5A.008.
A coin is tossed four times. What is the probability that the outcomes of the tosses are exactly in the order THTH?

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