A painter needs to cover the walls of four rooms In two coats of paint. Each room measures 4 ft by 8 ft, and the celling is 10 feet high in each. Each gallon of paint covers 32 square feet. How many gallons of paint does he need?
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First, let's calculate the total wall area of each room. Each room has four walls, so the area of the walls in one room is given by the formula: 2*(length + width) * height. For a room measuring 4 ft by 8 ft and a height of 10 ft, the wall area is 2*(4 + 8) * 10 = 240 square feet per room. For four rooms, the total wall area is 240 sq ft * 4 = 960 square feet. Since the painter needs two coats, we double this to get 1920 square feet. Each gallon of paint covers 32 square feet, so the painter will need 1920 / 32 = 60 gallons of paint. It's always a good idea to factor in a little extra for touch-ups! When calculating how much paint you need, many painters recommend adding about 10% more to account for absorption by the walls or any mishaps while painting. In this case, that would be around 6 additional gallons, bringing the total to about 66 gallons—better safe than sorry when you're transforming those rooms!